Answer:
Step-by-step explanation:
Red =x Blue = y
1) 4x + 6y = 180
2) x + y = 40
solve for x in eq. 2 and plug into eq. 1
2a) x=40-y
1a) 4(40-y) + 6y = 180
160-4y +6y = 180
2y=20
y=10
plug into eq. 2
x + 10 =40
x=30
30 red packages
;) maybe a late Christmas gift.. :D
Answer:
Step-by-step explanation:
Answer:
3 is correct answer
Step-by-step explanation:
hope it helped you:)
Using Laplace transform we have:L(x')+7L(x) = 5L(cos(2t))sL(x)-x(0) + 7L(x) = 5s/(s^2+4)(s+7)L(x)- 4 = 5s/(s^2+4)(s+7)L(x) = (5s - 4s^2 -16)/(s^2+4)
=> L(x) = -(4s^2 - 5s +16)/(s^2+4)(s+7)
now the boring part, using partial fractions we separate 1/(s^2+4)(s+7) that is:(7-s)/[53(s^2+4)] + 1/53(s+7). So:
L(x)= (1/53)[(-28s^2+4s^3-4s^2+35s-5s^2+5s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]L(x)= (1/53)[(4s^3 -37s^2 +40s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]
denoting T:= L^(-1)and x= (4/53) T(s^3/(s^2+4)) - (37/53)T(s^2/(s^2+4)) +(40/53) T(s^2+4)-(4/53) T(s^2/s+7) +(5/53)T(s/s+7) - (16/53) T(1/s+7)
Answer:
a
b
c 0 customers
Step-by-step explanation:
Given
per customer
Solving (a): Amount (A) on n customers
This is calculated as:
Solving (b): Amount on 134 customers
In this case: n = 134
So:
Solving (c): Customers at noon.
At noon, the amount is 30.
So:
Collect like terms