The series as represented in the task content is divergent and hence; diverges.
<h3>What convergence and divergence in series?</h3>
It follows from the task content that the series defined by the summation expression as represented above is to be identified as divergent or convergent.
It is noteworthy to know that;
If a sequence converges, it means that the limit of the sequence exists as n → ∞. Also, if the limit of the sequence as n → ∞ does not exist, Then, such series is said to diverges.
Therefore, by evaluation as the limit of the expression k sin²k / 1 + k³ as k → ∞ is; Undefined and hence does not exist.
Read more on convergence and divergence of series;
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(3 + (2/3))(2+(1/2) = 3*2+2*(2/3)+3*(1/2)+((2/3)(1/2)) = 6+(4/3) +(3/2) + (2/6) = 6 + ((8+9+2)/6) = 6 + (19/6) = 6 + 3 + 1/6 = 9 + 1/6 miles = D
What are you even asking us
Answer:
x = 38
y = 41
z = 123
Step-by-step explanation:
x + y + z = =202
y = x + 3
z = 3y = 3(x + 3) = 3x + 9
<u>x</u> + <u>y</u> + <u>z</u> = <u>x</u> + <u>x + 3</u> + <u>3x + 9</u> = 5x + 12 = 202
5x + 12 = 202
5x = 190
x = 38
y = x + 3 = 41
z = 3y = 123
Answer:
False
Step-by-step explanation:
1+8=9
9+10=19
1y+8y=9y
9y+10y=19y
19y=20y
The equations dont match.
Hence, the equation is false.
