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expeople1 [14]
3 years ago
6

i need info on 3 cars, including make, model and selling price. then i need each cars depreciation rate. ill give brainliest. (p

ls include links of where you got the info. im desperate)
Mathematics
1 answer:
myrzilka [38]3 years ago
3 0

Answer:

1) Mercedes Benz A class which is $ 33495 (starting),

made in Germany

https://www. truecar .com/prices-new/mercedes - benz/

It has depreciation 6% in the first three years  https://   www .themoneycalculator  .com/vehicle-finance/calculators/car-depreciation-by-make-and-model/MERCEDES-BENZ/A_CLASS/

2) Ferrari 458  $35,563

https://   www.   ferrari.  com/en-EN/auto/458-speciale

Ferrari 458 models depreciate 29% in the first three years

https://www.    themoneycalculator      .com/vehicle-finance/calculators/car-depreciation-by-make-and-model/FERRARI/458/

3)Honda Civic $20,950  

https://    automobiles   .honda         .com/civic

depreciation is 34%

https://    www.       themoneycalculator   .com   /vehicle-finance/calculators/car-depreciation-by-make-and-model/HONDA/CIVIC/

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Solve using elimination method
irga5000 [103]
X+y=8

2x²-y=-5        add them up so that to eliminate y
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2x²+x+oy=3 ===> 2x²+x=3

6 0
3 years ago
Are 5x and x+5 equivalent expressions?
valkas [14]
No,

5x means 5 is being multiplied by a number (x)

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Hope this helps ;)
7 0
3 years ago
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A chemical plant has an emergency alarm system. When an emergency situation exists, the alarm sounds with probability 0.95. When
Lapatulllka [165]

Answer:

6.56% probability that a real emergency situation exists.

Step-by-step explanation:

We have these following probabilities:

A 0.4% probability that a real emergency situation exists.

A 99.6% probability that a real emergency situation does not exist.

If an emergency situation exists, a 95% probability that the alarm sounds.

If an emergency situation does not exist, a 2% probability that the alarm sounds.

The problem can be formulated as the following question:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem:

What is the probability of a real emergency situation existing, given that the alarm has sounded.

P(B) is the probability of there being a real emergency situation. So P(B) = 0.004.

P(A/B) is the probability of the alarm sounding when there is a real emergency situation. So P(A/B) = 0.95.

P(A) is the probability of the alarm sounding. This is 95% of 0.4%(real emergency situation) and 2% of 99.6%(no real emergency situation). So

P(A) = 0.95*0.04 + 0.02*0.996 = 0.05792

Given that the alarm has just sounded, what is the probability that a real emergency situation exists?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.004*0.95}{0.05792} = 0.0656

6.56% probability that a real emergency situation exists.

6 0
3 years ago
What is the inverse of the function f(x) = 1/9x+2
Lady bird [3.3K]

Hello,

f(x) = 1/9x + 2 ⇔ y = 1/9x + 2 ⇔ 1/9x = y - 2 ⇔ x = 9(y - 2)

                                                                            x = 9y - 18

⇒ f⁻¹(x) = 9x - 18

3 0
2 years ago
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Answer:

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Step-by-step explanation:

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