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koban [17]
2 years ago
15

If you needed to reflect (-4,-5) over the y-axis what would the coordinates be?

Mathematics
2 answers:
Triss [41]2 years ago
6 0
Answer: The coordinates would be (4,-5)
lisov135 [29]2 years ago
6 0

It would be (4, -5)

Hope this helps!

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Hello, happy Friday, I am just here with some geometry questions.
Hatshy [7]

Answer:

B

Step-by-step explanation:

So far, we know that:

∠D = ∠J.

And that:

DE:JK = 14:7 = 2:1

So, to prove that ΔDEF ~ ΔJKL by SAS, DF must be similar to JL, as those are the sides between the angle.  

So:

DF:JL = 2:1.

Our answer is B.

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2 years ago
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DaniilM [7]

Answer:

Mia is correct.

Step-by-step explanation:

You can see this if you write 5/11 in a calculator, you get 0.454545454545 infinitely. In other cases, you would write it like Malik said if the answer were to be 0.455555555, but it isn't.

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What is solution to 3/5=z/10
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Z=6

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I am a 2 digit number the sum of my digits is 6. I have both 2 and 7 as factors
gogolik [260]
The number is 5 and the factor is 1
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3 years ago
Help ASAP please!!!!!!!!!​​
Katena32 [7]

Answer:

Δ JKL is similar to Δ ABC ⇒ D

Step-by-step explanation:

Similar triangles have equal angles in measures

In ΔABC

∵ m∠A = 15°

∵ m∠B = 120

∵ The sum of the measures of the interior angles of a Δ is 180°

∴ m∠A + m∠B + m∠C = 180°

→ Substitute the measures of ∠A and ∠B

∵ 15 + 120 + m∠C = 180

→ Add the like terms in the left side

∴ 135 + m∠C = 180

→ Subtract 135 from both sides

∴ 135 - 135 + m∠C = 180 - 135

∴ m∠C = 45°

The similar Δ to ΔABC must have the same measures of angles

If triangles ABC and JKL are similar, then

m∠A must equal m∠J

m∠B must equal m∠K

m∠C must equal m∠L

∵ m∠J = 15°

∴ m∠A = m∠J

∵ m∠L = 45°

∴ m∠C = m∠L

∵ m∠J + m∠K + m∠L = 180°

→ Substitute the measures of ∠J and ∠L

∵ 15 + m∠K + 45 = 180

→ Add the like terms in the left side

∴ 60 + m∠K = 180

→ Subtract 60 from both sides

∴ 60 - 60 + m∠K = 180 - 60

∴ m∠K = 120°

∴ m∠B = m∠K

∴ Δ JKL is similar to Δ ABC

6 0
3 years ago
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