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Katyanochek1 [597]
1 year ago
5

To find the volume of a rectangular prism you multiply the 3 dimensions, length x width x height. What combination of numbers wi

ll give me a volume of 17?
Mathematics
2 answers:
aleksklad [387]1 year ago
8 0
1, 1 and 17. Since 17 is a prime number, there isn’t exactly numbers that are multiplied by each other that give 17.
inysia [295]1 year ago
6 0

Answer:

1, 1, 17

Step-by-step explanation:

17 is a prime number. This means the only factors are 1, and 17. This means that since only 17, and 1 multiply to 17, to get a volume of 17 you can only use 1, and 17 (1, 1, and 17)

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Please help and answer why
Brilliant_brown [7]

2 sticks of butter

5-1=4

4/2=2

She already makes 1 cake so we can subtract 5-1

2 cakes can be made per stick of butter so we do 4/2 which is 2

8 0
3 years ago
Barbara is a research biologist for Green Carpet Lawns. She is studying the effects of fertilizer type, temperature at time of a
slega [8]

Answer: 90

Step-by-step explanation:

Given : The number of fertilizer types = 6

The number of temperature zones =5

The number of water treatments=3

The number of different lawn plots =6\times5\times3=90

Hence, the number of different lawn plots she needs in order to test each fertilizer type, temperature range, and water treatment configuration =90

5 0
3 years ago
Read 2 more answers
100 points and brainliest
Vlad [161]

Answer:

x= 90 degrees because AD is the perpendicular bisector and the angle bisector

y=86 degrees because 47+47+86=180

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
ASAP. Can someone help me find the percentage of these please, I can't figure it out. (Pic below)
atroni [7]

Answer:

Interphase: 55.56%

Prophase: 27.78%

Metaphase: 8.33%

Anaphase: 5.56%

Telophase: 2.78%

Step-by-step explanation:

All you need to do is follow the instructions. To get the percentage, all you need to do is divide the part by the whole then multiply it by 100%.

\dfrac{Part}{Whole}\times 100\%

Now let's take your problem:

Number of cells in interphase:

20 this is the part and the whole would be the total cells, which is 36. Now we insert that into our equation:

\dfrac{20}{36}\times 100\%=0.5556\times100\%=55.56\%

So now we apply the same to the rest:

Prophase:

\dfrac{10}{36}\times 100\%=0.2778\times100\%=27.78\%

Metaphase:

\dfrac{3}{36}\times 100\%=0.0833\times100\%=8.33\%

Anaphase:

\dfrac{2}{36}\times 100\%=0.0556\times100\%=5.56\%

Telophase:

\dfrac{1}{36}\times 100\%=0.0278\times100\%=2.78\%

4 0
3 years ago
In a simple random sample of 14001400 young​ people, 9090​% had earned a high school diploma. Complete parts a through d below.
ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has ​increased.

Step-by-step explanation:

Let <em>p</em> = proportion of young people who had earned a high school diploma.

A sample of <em>n</em> = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

\hat p=0.90

(a)

The standard error for the estimate of the percentage of all young people who earned a high school​ diploma is given by:

SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

Compute the standard error value as follows:

SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

       =\sqrt{\frac{0.90(1-0.90)}{1400}}\\

       =0.008

Thus, the standard error for the estimate of the percentage of all young people who earned a high school​ diploma is 0.0080.

(b)

The margin of error for (1 - <em>α</em>)% confidence interval for population proportion is:

MOE=z_{\alpha/2}\times SE_{\hat p}

Compute the critical value of <em>z</em> for 95% confidence level as follows:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the margin of error as follows:

MOE=z_{\alpha/2}\times SE_{\hat p}

          =1.96\times 0.0080\\=0.01568\\\approx1.6\%

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has​ increased, the hypothesis is defined as:

<em>H₀</em>: The percentage of young people who earn high school diplomas has not​ increased, i.e. <em>p</em> = 0.80.

<em>Hₐ</em>: The percentage of young people who earn high school diplomas has not​ increased, i.e. <em>p</em> > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of <em>p</em>, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has ​increased.

8 0
3 years ago
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