Thea dissolves 0.33 mole of glucose into 450 mL of water. What is the concentration of the solution?

Según la ecuación, HNO3 + H2S ----------- NO + S+ H2O el elemento que se oxida es

Serhud [2]

Answer:

HNO3 + H2S = H2O + NO + S - Chemical Equation Balancer. Balanced Chemical Equation. 2 HNO 3 + 3 H 2 S → 4 H 2 O + 2 NO + 3 S. Reaction Information. Nitric Acid + Hydrogen Sulfide = Water + Nitric Oxide (radical) + Sulfur . Reactants.

Explanation:

5 0

3 years ago

7. What type of water pollution is produced from chemicals used to kill bugs and weeds?

Serga [27]

Answer:

Groundwater pollution

Explanation:

Pesticides, when sprayed on crop plants, are able to flow below the surface of the ground, reaching water-bearing aquifers, thereby contaminating groundwater, making it unsuitable for both human and agricultural uses.

5 0

3 years ago

Why should a sports person or a rickshaw puller in take more corbohydrate rich food in their diet

Taya2010 [7]

Answer:

These glucose molecules are stored in the liver and muscles to be used for fuel, especially during physical activity. Carbohydrates improve athletic performance by delaying fatigue and allowing an athlete to compete at higher levels for longer. nutrients, such as fat or muscle protein, are utilized to make energy.

Explanation:

7 0

2 years ago

How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2 (aq) + Na2

jeyben [28]

Answer: The amount of barium sulfate produced in the given reaction is 0.667 grams.

Explanation:

To calculate the number of moles from molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of barium chloride = 0.113 M

Volume of barium chloride = 25.34 mL = 0.02534 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.113mol/L=\frac{\text{Moles of barium chloride}}{0.02534L}\\\\\text{Moles of barium chloride}=0.00286mol$

For the given chemical reaction:

$BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow BaSO_4(s)+2NaCl(aq.)$

By Stoichiometry of the reaction:

1 mole of barium chloride is producing 1 mole of barium sulfate.

So, 0.00286 moles of barium chloride will produce = $\frac{1}{1}\times 0.00286mol=0.00286mol$ of barium sulfate.

Now, to calculate the mass of barium sulfate, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of barium sulfate = 233.38 g/mol

Moles of barium sulfate = 0.00286 moles

Putting values in above equation, we get:

$0.00286mol=\frac{\text{Mass of barium sulfate}}{233.38g/mol}\\\\\text{Mass of barium sulfate}=0.667g$

Hence, the amount of barium sulfate produced in the given reaction is 0.667 grams

4 0

3 years ago

How many moles of iron would be needed to react with 3.82 moles of oxygen

Rashid [163]

Answer:

5.09

Explanation:

8 0

3 years ago