<span>C + O2 → CO2
(8,376,726 tons) x (0.80) / (12.01078 g C/mol) x (1 mol CO2/ 1 mol C) x
(44.00964 g CO2/mol) = 24,555,054 tons CO2</span>
Answer:
1.414 Moles
Solution:
Data Given:
Mass of MgS₂O₃ = 193 g
M.Mass of MgS₂O₃ = 136.43 g.mol⁻¹
Moles = ?
Formula Used:
Moles = Mass ÷ M.Mass
Putting values,
Moles = 193 g ÷ 136.43 g.mol⁻¹
Moles = 1.414 mol
It's a cyclohexane ring with an ethyl group at 1 and a methyl group at 3. The Ethyl group is bigger and more important group get's the first position.
1-ethyl-3-methylcyclohexane
Answer:
2-ethly-3-5 dimethylheptam
Explanation:
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