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Eva8 [605]
3 years ago
13

What is the equation for concentration with Solutes and Solvents?​

Chemistry
1 answer:
QveST [7]3 years ago
5 0

Answer:

 Molarity = no. of moles of solute / Liter of solution

  Molality = no. of moles of solute / Kilogram of solvent

Explanation:

Solvent: Solvent is a liquid that dissolve the solute. in most cases it is water but some time other liquids gases can also be a solvent.solvent have the ability to dissolve solute and in larger volume than solute.

Solute:

It is the substance that is in less amount than solvent and dissolve in it

Solution:

When solvent and solute combines, the solute get dissolved in it and it form a solution.

Concentration:

It is to represent or describe the property of solution and refer to the amount of one constituent per total mixture or solvent.

There are two terms to represent the concentration in terms of solute and solvent.

Molarity:

It the amount of solute in moles dissolved per liter of solution. it can be represented by the following equation

         Molarity = no. of moles of solute / Liter of solution

Molality:

It is the amount of solute in moles dissolved per kilogram of solvent. it can be representd by the following equation

           Molality = no. of moles of solute / Kilogram of solvent

           

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a 4.50 g coin of copper absorbed 54 calories of heat. what was the final temperature of the copper if the initial temperature wa
vlada-n [284]

Answer:

Final temperature =  T₂ = 155.43 °C

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of coin = 4.50 g

Heat absorbed = 54 cal

Initial temperature = 25 °C

Specific heat of copper = 0.092 cal/g °C

Final temperature = ?

Solution:

Q = m.c. ΔT

ΔT = T₂ -T₁

Q = m.c. T₂ -T₁

54 cal = 4.50 g × 0.092 cal/g °C ×  T₂ -25  °C

54 cal = 0.414 cal/ °C ×  T₂ -25  °C

54 cal /0.414 cal/ °C =  T₂ -25  °C

130.43 °C  =  T₂ -25 °C

130.43 °C + 25 °C = T₂

155.43 °C = T₂

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