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german
3 years ago
8

Calculate the pressure in the atmosphere of 2.00 moles of helium gas in a 10.0 L container at 27 C

Chemistry
1 answer:
Jet001 [13]3 years ago
4 0

Answer:

The pressure is 4.926 atm

Explanation:

<u>Step 1:</u> Data given

Number of moles = 2.00 moles

Volume of the gas = 10.0 L

Temperature = 27 °C = 273 + 27 = 300 Kelvin

<u>Step 2:</u> Calculate the pressure

P*V = n*R*T

with P= TO BE DETERMINED

with V = 10.0 L

with n = 2.00 moles

with R = 0.00821 L*atm/ K*mol

T = 300 Kelvin

P = (n*R*T) / V = (2 * 0.00821 * 300) / 10 L = 4.926 atm

The pressure is 4.926 atm

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The mass percent of Al(OH)₃ is 15.3%

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The total moles of HCl is:

n_{HCl,total} =M_{HCl} *V_{HCl} =0.111*0.025=2.78x10^{-3} moles

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The difference between the total and excess of HCl, it can be know the moles that reacts with the aluminum hydroxide, is:

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