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german
3 years ago
8

Calculate the pressure in the atmosphere of 2.00 moles of helium gas in a 10.0 L container at 27 C

Chemistry
1 answer:
Jet001 [13]3 years ago
4 0

Answer:

The pressure is 4.926 atm

Explanation:

<u>Step 1:</u> Data given

Number of moles = 2.00 moles

Volume of the gas = 10.0 L

Temperature = 27 °C = 273 + 27 = 300 Kelvin

<u>Step 2:</u> Calculate the pressure

P*V = n*R*T

with P= TO BE DETERMINED

with V = 10.0 L

with n = 2.00 moles

with R = 0.00821 L*atm/ K*mol

T = 300 Kelvin

P = (n*R*T) / V = (2 * 0.00821 * 300) / 10 L = 4.926 atm

The pressure is 4.926 atm

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4 0
2 years ago
Determine the specific heat ofmaterial if a 12g sample absorbed 48j as it was heated from 20-40
devlian [24]

Answer:

c =0.2 J/g.°C

Explanation:

Given data:

Specific heat of material = ?

Mass of sample = 12 g

Heat absorbed = 48 J

Initial temperature = 20°C

Final temperature = 40°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  40°C -20°C

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6 0
2 years ago
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zubka84 [21]

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Kb(C</span>₅H₅N) = 1.4·10⁻⁹.
[C₅H₅NH⁺] = [OH⁻] = x; equilibrium concentration.<span>
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Kb = [C₅H₅NH⁺] · [OH⁻] / [C₅H₅N].

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kirza4 [7]
I believe the answer is increases , decreases
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