Answer: see proof below
<u>Step-by-step explanation:</u>
Use the Sum & Difference Identity: cos (A + B) = cos A · cos B - sin A · sin B
Recall the following from Unit Circle: cos (π/2) = 0, sin (π/2) = 1
cos (π) = -1, sin (π) = 0
Use the Quotient Identity: 
<u>Proof LHS → RHS:</u>




Quotient: tan x
LHS = RHS 
10/2.5=4 So, we should multiply it by 4
4x4=16 width
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Answer:
f(g) = -3( x^2 -x-6) -6 = -3x^2+3x+12
In case of plane, for y intercept, x and z are o .
So we will get
4(0)+5y-0=20
5y=20
Dividing both sides by 5
y = 4
So the y intercept is (0,4,0).
In second question, x intercept is 1, y intercept is -1 and z intercept is 2 .
So the correct option is the third equation , that is x-y+2z=4 .
Answer:184ft²
Step-by-step explanation:2(5×10)+2(4×6/2)+(6×10)
100+24+60=184
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