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Illusion [34]
3 years ago
11

155% is equivalent to what fraction in reduced terms

Mathematics
1 answer:
Bond [772]3 years ago
3 0
It is 1 55/100. Reduced that is 1 11/20
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Identify the vertex of the parabola plssss..!!!!!!
kherson [118]

Answer:

how to do this

Step-by-step explanation:

8 0
3 years ago
There are 70 sixth graders at Wilson Middle School. Only 40% of the sixth graders will attend the morning assembly. How many six
love history [14]

Answer: 42

Step-by-step explanation:

We know that because 40% percent of 70 equals 28. So we do the following-

70 minus 28 equals 42!

Glad to help!

8 0
3 years ago
If x=2 and y=3 what is 7x+y+16
Vinvika [58]

Answer: 33

Step-by-step explanation:

Input the numbers into the variables.
7(2) + 3 + 16

14 + 3 + 16

17 + 16

33

3 0
2 years ago
Set up the integral that represents the arc length of the curve f(x) = ln(x) + 5 on [1, 3], and then use Simpson's Rule with n =
marta [7]

Answer:

The integral for the arc of length is:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx

By using Simpon’s rule we get: 1.5355453

And using technology we get:  2.3020

The approximation is about 33% smaller than the exact result.

Explanation:

The formula for the length of arc of the function f(x) in the interval [a,b] is:

\displaystyle\int_a^b \sqrt{1+[f'(x)]^2}dx

We need the derivative of the function:

f'(x)=\frac{1}{x}

And we need it squared:

[f'(x)]^2=\frac{1}{x^2}

Then the integral is:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx

Now, the Simposn’s rule with n=4 is:

\displaystyle\int_a^b g(x)}dx\approx\frac{\Delta x}{3}\left( g(a)+4g(a+\Delta x)+2g(a+2\Delta x) +4g(a+3\Delta x)+g(b) \right)

In this problem:

a=1,b=3,n=4, \displaystyle\Delta x=\frac{b-a}{n}=\frac{2}{4}=\frac{1}{2},g(x)= \sqrt{1+\frac{1}{x^2}}

So, the Simposn’s rule formula becomes:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\\\approx \frac{\frac{1}{3}}{3}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{1}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(1+\frac{2}{2}\right)^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{3}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)

Then simplifying a bit:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx \approx \frac{1}{9}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(\frac{3}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(2\right)^2}} +4\sqrt{1+\frac{1}{\left(\frac{5}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)

Then we just do those computations and we finally get the approximation via Simposn's rule:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\approx 1.5355453

While when we do the integral by using technology we get: 2.3020.

The approximation with Simpon’s rule is close but about 33% smaller:

\displaystyle\frac{2.3020-1.5355453}{2.3020}\cdot100\%\approx 33\%

8 0
3 years ago
A pizza parlor charges $18 for a plain pizza and charges $0.75 for each additional topping.
Georgia [21]

Answer:

the last one

Step-by-step explanation:

well you have 18 pizzas total, and each topping is 0.75. so let's say u want two toppings you would do 75 ×2 and so on, you would label the question

Y= 0.75x + 18

5 0
3 years ago
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