Please help I really need to pass this exam
If line GF is a midsegment of triangle CDE, find CD.
2 answers:
CF = FG = GC because it is equilateral triangle
So
3x + 0.8 = 2x + 3
3x–2x = 3 – 0.8
X = 2.2
Putting this value to DE
IT IS ALSO A EQUILATERAL TRIANGLE
SO
5x + 4 = 5× 2.2 +4 =
11+4 = 15
All side will be 15 of triangle CD = DC = CE = 15
Mark as brainliest
Answer:
Step-by-step explanation:
We have been given a triangle CDE in which GF is mid-segment. we are asked to find the value of CD.
We know that the length of mid-segment of a triangle is half the measure of third side.
Using triangle mid-segment theorem, we can set an equation as:
Switch sides:
Since F is midpoint of CD, so we can set an equation as:
Therefore, the length of CD is 13.6 units.
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I got 6.3 not sure if Im right
The answer is 6.625. :D .
Answer:
$8.75 is your answer.
Step-by-step explanation:
What you do is you multiply 1.25 by 7.
<em>1.25 x 7 = $8.75</em>
$8.75 is your answer.