Question

Please help I really need to pass this exam If line GF is a midsegment of triangle CDE, find CD.

Answer 1

CF = FG = GC because it is equilateral triangle

So
3x + 0.8 = 2x + 3

3x–2x = 3 – 0.8

X = 2.2

Putting this value to DE

IT IS ALSO A EQUILATERAL TRIANGLE

SO
5x + 4 = 5× 2.2 +4 =

11+4 = 15

All side will be 15 of triangle CD = DC = CE = 15



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Answer 2

Answer:

$CD=13.6$

Step-by-step explanation:

We have been given a triangle CDE in which GF is mid-segment. we are asked to find the value of CD.

We know that the length of mid-segment of a triangle is half the measure of third side.

Using triangle mid-segment theorem, we can set an equation as:

$2(2x+3)=5x+4$

$4x+6=5x+4$

Switch sides:

$5x+4=4x+6$

$5x-4x+4=4x-4x+6$

$x+4=6$

$x+4-4=6-4$

$x=2$

Since F is midpoint of CD, so we can set an equation as:

$CD=2(3x+0.8)$

$CD=2(3(2)+0.8)$

$CD=2(6+0.8)$

$CD=2(6.8)$

$CD=13.6$

Therefore, the length of CD is 13.6 units.