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Vera_Pavlovna [14]
3 years ago
15

Which of the following equations represent a proportional relationship

Mathematics
1 answer:
MAXImum [283]3 years ago
8 0
A would be fine as your answer.
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Find the value of each variable in the parallelogram.
Nikitich [7]

Answer:

u = 4; v = 18

because this is a parallelogram

=> 2u + 2 = 5u - 10

6 = v/3

<=> 3u = 12

v = 6.3

<=> u = 4

v = 18

7 0
2 years ago
Solve the equation 2(9x-6)=6(3x-2)+2
weqwewe [10]

Answer:

There are no solutions.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2(9x−6)=6(3x−2)+2

(2)(9x)+(2)(−6)=(6)(3x)+(6)(−2)+2(Distribute)

18x+−12=18x+−12+2

18x−12=(18x)+(−12+2)(Combine Like Terms)

18x−12=18x+−10

18x−12=18x−10

Step 2: Subtract 18x from both sides.

18x−12−18x=18x−10−18x

−12=−10

Step 3: Add 12 to both sides.

−12+12=−10+12

0=2

4 0
3 years ago
Read 2 more answers
If 20 tickets to a carnival cost $120.00, make a
aivan3 [116]
120/20=6 so it’s six dollars a ticket
1=$6
3=$18
4=$24
5=$30
6=$36
n=6n
8 0
2 years ago
Find the product of 30−−√ and 610−−√. Express it in standard form (i.E., ab√).
Zina [86]

we are given

\sqrt{30} *\sqrt{610}

we can radical formula

\sqrt{a} *\sqrt{b}=\sqrt{a*b}

we get

\sqrt{30} *\sqrt{610}=\sqrt{30*610}

\sqrt{30} *\sqrt{610}=\sqrt{3*61*100}

we can  also write as

\sqrt{30} *\sqrt{610}=\sqrt{100}*\sqrt{3*61}

\sqrt{30} *\sqrt{610}=10\sqrt{183}............Answer


7 0
3 years ago
Read 2 more answers
5x times 4y equal to 3x times 5y
makvit [3.9K]

I’m guessing you want oh know what x and y are?

If so isolate the variable and do the inverse of the operation

If not please correct me ^^

3 0
3 years ago
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