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3 years ago

Which equation shows y=−1/2x+4 is in standard form?

Mathematics

1 answer:

adelina 88 [10]3 years ago

8 0

Answer:

B. x + 2y = 8 is your answer.

Step-by-step explanation:

So this is what you do:

y = -1/2x + 4 <u>You are going to add -1/2 to the other side.</u>

y + 1/2x = 4 <u>You are going to multiply the equation by 2.\</u>

B. x + 2y = 8 is your answer.

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The probability of drawing a yellow triangle is 3/5. If you replace the card, how many times will you draw a yellow triangle out

JulijaS [17]

Answer:

150 times

Step-by-step explanation:

From the question given,

The probability of drawing a yellow triangle is 3/5 with replacement. This means that the probability of drawing a yellow card any time, will be 3/5.

For 250 draws,

The number of times a yellow triangle will appear will be = (3/5)x250 = 150

3 0

3 years ago

What is the weight in ounces of a 3/4 pound fish

g100num [7]

It would be 12 ounces.

7 0

3 years ago

Read 2 more answers

The mean amount purchased by a typical customer at Churchill's Grocery Store is $23.50 with a standard deviation of $5.00. Assum

DochEvi [55]

Answer:

a. $\mathtt{P(X \geq 25) =0.0170}$ ( to four decimal places)

b. $P(22.5$ ( to four decimal places )

c. The limits will be between the interval of ( 22.33,24.67 )

Step-by-step explanation:

Given that :

mean = 23.50

standard deviation = 5.00

sample size = 50

The objective is to calculate the following:

(a) What is the likelihood the sample mean is at least $25.00?

Let X be the random variable, the probability that the sample mean is at least 25.00 is:

$P(X \geq 25) = 1 - P(\dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}} < \dfrac{25- 23.50}{ \dfrac{5}{\sqrt{ 50}} })$

$P(X \geq 25) = 1 - P(Z< \dfrac{1.5}{ \dfrac{5}{7.07107}} })$

$P(X \geq 25) = 1 - P(Z< \dfrac{1.5 \times 7.071}{ {5}})$

$P(X \geq 25) = 1 - P(Z< 2.1213)$

$P(X \geq 25) = 1 - P(Z< 2.12)$ to two decimal places

From the normal tables :

$P(X \geq 25) = 1 - 0.9830$

$\mathtt{P(X \geq 25) =0.0170}$ ( to four decimal places)

(b) What is the likelihood the sample mean is greater than $22.50 but less than $25.00?

$P(22.5$

$P(22.5$ to four decimal places

At 90 % confidence interval, level of significance = 1 - 0.90 = 0.10

The critical value for the $z_{\alpha/2} = 0.05$ = 1.65

Standard Error = $\dfrac{\sigma}{\sqrt{n}}$

Standard Error = $\dfrac{5}{\sqrt{50}}$

Standard Error = 0.7071

Therefore, at 90 percent of the sample means, the limits will be between the intervals of : $(\mu \pm z_{\alpha/2} \times S.E)$

Lower limit = ( 23.5 - (1.65×0.707) )

Lower limit = ( 23.5 - 1.16655 )

Lower limit = 22.33345

Lower limit = 22.33 (to two decimal places).

Upper Limit = ( 23.5 + (1.65*0.707) )

Upper Limit = ( 23.5 + 1.16655 )

Upper Limit = 24.66655

Upper Limit = 24.67

The limits will be between the interval of ( 22.33,24.67 )

6 0

3 years ago

Write an equation of a line containing (2, 1) and (3, 4) in point-slope form.

ivann1987 [24]

Answer:

$y-1=3(x-2)$

$y-4=3(x-3)$

Step-by-step explanation:

The slope formula is given by:

$m=\frac{y_2-y_1}{x_2-x_1}$

The line containing (2, 1) and (3, 4) has slope;

$m=\frac{4-1}{3-2}=3$

The point-slope form is given by:

$y-y_1=m(x-x_1)$

We substitute the point and slope to get:

$y-1=3(x-2)$

$y-4=3(x-3)$

8 0

3 years ago

Given the function <img src="https://tex.z-dn.net/?f=g%28x%29%3Dm%28-2x%2B2%29%5E5-n" id="TexFormula1" title="g(x)=m(-2x+2)^5-n"

Alekssandra [29.7K]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

The given function g(x) is a continuous function, since, for any x we can find a real value of the function.

A. $\frac{d g(x)}{dx} = 5m(-2x + 2)^{4} \times (-2)$ .

Since, m is a constant, which is not equals to 0, the above value of the differentiation of the function, will be negative.

For x = 1, the above value is 0, that is at x = 1, the function has either maximum value, or a minimum value.

B. As per the above information, we have get that for x = 1, $\frac{d g(x)}{dx} = 0$ .

Hence, the function's critical point's x coordinate is x = 1.

The x- coordinate of the given point is not dependent on m or n.

Hence, proved.

4 0

3 years ago