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3 years ago

What is the range of the function y = -x ^2 + 1? y ≤ -1 y ≥ -1 y ≤ 1 y ≥ 1

Mathematics

2 answers:

kobusy [5.1K]3 years ago

6 0

$y \leqslant - 1$

rjkz [21]3 years ago

6 0

Answer:

$y\leq -1$

Step-by-step explanation:

$y = -x ^2 + 1$

Range is the set of y values for which the function is defined

To find out the range we look at the value of k in the vertex

$y = -x ^2 + 1$

General vertex form is : $y=a(x-h)^2+k$

where (h,k) is the vertex that is maximum when a is negative

From the given equation the value of k= -1

The graph reaches the maximum value at y=-1

So range is $y\leq -1$

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