A. ratio of areas = 2^2 /5^2 = 4/25
B 14^2 : 1 = 196:1
C. ratio of perimeters would be sqrt81 = 9 times
Answer:
43.8°
Step-by-step explanation:
Applying,
Cosine rule,
From the diagram attached,
x² = y²+z²-2yxcos∅.................... Equation 1
where ∅ = ∠YXZ
Given: x = 8.7 m, y = 10.4 m, z = 12.4 m
Substitute these values into equation 1
8.7² = 10.4²+12.4²-[2×10.4×12.4cos∅]
75.69 = (108.16+153.76)-(257.92cos∅)
75.69 = 261.92-257.92cos∅
collect like terms
257.92cos∅ = 261.92-75.69
257.92cos∅ = 186.23
Divide both sides by the coefficient of cos∅
cos∅ = 186.23/257.92
cos∅ = 0.722
Find the cos⁻¹ of both side.
∅ = cos⁻¹(0.7220)
∅ = 43.78°
∅ = 43.8°
200+50+4=254 is the answer
The length of each side of the larger square is 8 cm.
<u>Step-by-step explanation</u>:
Step 1 ;
- The combined area of two squares = 80 sq.cm
- The side of small square = x
- The side of larger square = 2x
Step 2 :
Area of the square = a^2
Area of small square + area of large square = 80
x^2 + (2x)^2 = 80
x^2 + 4x^2 = 80
5x^2 = 80
x^2 = 80/5
x^2 = 16
x = ±4
Step 3 :
Since length cannot be negative, the value of x= 4
∴ The length of the side of small square = 4cm
The length of the side of larger square = 2x = 8cm
Answer: x < 11.9
Step-by-step explanation:
