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Amiraneli [1.4K]

3 years ago

13

Sara goes on a slingshot ride in an amusement park. She is strapped into a spherical ball that has a radius 3*10^2 of centimeter

s. What is the volume of air in the spherical ball? Use this formula:volume of a sphere=4/3pi,r^3 , where r is the sphere’s radius.

1 answer:

oee [108]3 years ago

8 0

Answer:

volume of sphere =4/3.pi.r^3

Step-by-step explanation:

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The following data are the monthly salaries y and the grade point averages x for students who obtained a bachelor's degree in bu

ziro4ka [17]

Answer:

1.) 3833.8

2.) (3428.81 ; 4238.79)

Step-by-step explanation:

1.)

Point estimate of the salary for student with GPA of 3.

Using the regression model given :

Y = 2090.5 + 581.1x

x = 3

Y = 2090.5 + 581.1(3)

= 3833.8

2.)

95% confidence interval :

Y ± Tcritical * √MSE

Y = point estimate at x =3 ; = 3833.8

MSE = 21,284

Tcritical at 95% ; df = n-2 = 6-2 = 4

Tcritical(0.025 ; 4) = 2.776

√MSE = √21284 = 145.89036

Lower boundary : 3833.8 - 2.776(145.89036) = 3428.81

Upper boundary : 3833.8 + 2.776(145.89036) = 4238.79

(3428.81 ; 4238.79)

4 0

3 years ago

How do you solve this

djverab [1.8K]

You can use photo math

8 0

3 years ago

Which expression is equivalent to log Subscript w Baseline StartFraction (x squared minus 6) Superscript 4 Baseline Over RootInd

lora16 [44]

The logarithmic expression $\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}$ can be expressed as $\rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8)$ .

Given to us

$\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}$

<h3>Which expression is equivalent to $\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}$ ?</h3>

To solve the problem we will use the basic logarithmic properties,

$\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}$

Using the logarithmic property $\rm log_a\dfrac{x}{y} = log_ax-log_ay$ ,

$=\rm log_w{(x^2-6)^4} - log_w{\sqrt[3]{x^2-8}}$

Using the exponential property $\sqrt[m]{a^n} = a^{\frac{n}{m}}$ ,

$=\rm log_w{(x^2-6)^4} - log_w(x^2-8)^{\dfrac{1}{3}}$

Using the logarithmic property $\rm log_aB^x = xlog_aB$ ,

$=\rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8)$

Hence, the logarithmic expression $\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}$ can be expressed as $\rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8)$ .

Learn more about Logarithmic Expression:

brainly.com/question/7302008

5 0

3 years ago

452 divided by 7 with remaining

ozzi

Answer: The answer is 64 remaining 5.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Plss do #7 and #9 make sure to add why for brainliest :)

Sladkaya [172]

Answer:

7. Function A has the greater initial value.

9. Function A is nonlinear.

Function B is linear.

Step-by-step explanation:

7. The initial value of a function is the same as the y-intercept, or the value of y when x equals 0. For function A, the y-intercept is 4.

Function B is written in slope-intercept form, y = mx + b, where b represents the y-intercept. So, the y-intercept of function B is 3.

Finally, let's compare the y-intercepts of both functions. 4 is greater than 3, which means that Function A has the greater initial value.

9. A function is linear when the change in y over the change in x is proportional.

Function A: Let's look at the graph of Function A. It has points at (0, -1), (1, 0), and (2, 3). From point (0, -1) to point (1, 0), the value of x and the value of y both increase by 1. However, from point (1, 0) to point (2, 3), the value of x goes up by 1 but the value of y goes up by 3. Since the increase in y is not proportional, Function A is nonlinear.

Function B: Function B is written in the form y = mx, where m represents the change in y over the change in x. For this equation, m = 1. This means that every time the value of x increases by 1, the value of y increases by 1 as well. This represents a proportional relationship, so Function B is linear.

5 0

3 years ago