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Lyrx [107]
3 years ago
6

Plss do #7 and #9 make sure to add why for brainliest :)​

Mathematics
1 answer:
Sladkaya [172]3 years ago
5 0

Answer:

7. Function A has the greater initial value.

9. Function A is nonlinear.

Function B is linear.

Step-by-step explanation:

7. The initial value of a function is the same as the y-intercept, or the value of y when x equals 0. For function A, the y-intercept is 4.

Function B is written in slope-intercept form, y = mx + b, where b represents the y-intercept. So, the y-intercept of function B is 3.

Finally, let's compare the y-intercepts of both functions. 4 is greater than 3, which means that Function A has the greater initial value.

9. A function is linear when the change in y over the change in x is proportional.

Function A: Let's look at the graph of Function A. It has points at (0, -1), (1, 0), and (2, 3). From point (0, -1) to point (1, 0), the value of x and the value of y both increase by 1. However, from point (1, 0) to point (2, 3), the value of x goes up by 1 but the value of y goes up by 3. Since the increase in y is not proportional, Function A is nonlinear.

Function B: Function B is written in the form y = mx, where m represents the change in y over the change in x. For this equation, m = 1. This means that every time the value of x increases by 1, the value of y increases by 1 as well. This represents a proportional relationship, so Function B is linear.

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Answer: 3 1/4 + 7

Step-by-step explanation:

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Evaluate pq÷4; use p=14, and q=14​
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3 years ago
Five standard six-sided dice are rolled. We are told there is no three-of-a-kind, but there is a pair of dice that show the same
Neko [114]

The probability that after re-rolling these three dice, at least three of the five dice show the same value is  \frac{4}{9}

Of the three dice rolled, one may match the original pair and two are different, and this can occur three ways:

(\frac16 \times \frac56 \times \frac56 ) + ( \frac56 \times \frac16 \times \frac56 ) + ( \frac56 \times \frac 56 \times \frac 16 )  =  \frac {75}{216}

[ where \frac{1}{6} is the probability of matching the first two and \frac{5}{6} is the probability of not matching the first two ]

Or, two may match the original pair and one is different

( \frac16 \times \frac16 \times \frac 56 ) + ( \frac16 \times \frac56 \times \frac 16 ) + ( \frac56 \times \frac16 \times \frac16 )  = \frac {15}{216}

Or, all three may match the original pair

( \frac 16 \times \frac 16 \times \frac 16 )  = \frac {1}{216}

Or, all three may  be the same, but not match the original pair:

( \frac 56 \times \frac 16 \times\frac 16 )  =  \frac {5}{216}

[ where \frac{5}{6} is the probability of getting a new number and \frac{1}{6} is the probability of matching that new number ]

Adding these together: \frac {75}{216} + \frac {15}{216} + \frac 1{216} + \frac 5{216}  =  \frac {96}{216}  = \frac 49

To learn more about probability with the given link

brainly.com/question/11234923

#SPJ4

3 0
2 years ago
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