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3 years ago

Which of the following most closely represents a Democratic Party viewpoint?

Mathematics

1 answer:

FrozenT [24]3 years ago

8 0

Answer: Government should provide additional resources to help low income families

Step-by-step explanation:

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Ms.Holmes decided to water her plants.She had 2 1/2 gallons of water.She gave each plant 1/4 gallon of water.Which expression co

Inessa [10]

Answer:

(1/4)x=2 1/2

Step-by-step explanation:

It is 2.5 gal. of water and 0.25 gal. of water per plant.

It could also be x=(1/4)/(2 1/2)

6 0

3 years ago

Thomas made 8700 ml of tomato soup.he packed 1.6L of the soup in his kids lunches .he then froze half of the remaining soup.

kenny6666 [7]

Answer: 3550

Step-by-step explanation:

1.6L equals 1600mL

8700-1600=7100 remaining

7100 divided by 2 = 3550

7 0

3 years ago

Divide 3 by 4, then subtract z from the result

8_murik_8 [283]

Answer:

3/4 = z

Step-by-step explanation:

<u>Step 1: Convert words into an expression</u>

Divide 3 by 4, then subtract z from the result

3/4 - z

<u>Step 2: Solve for z</u>

3/4 - z + z = 0 + z

3/4 = z

Answer: 3/4 = z

7 0

3 years ago

Read 2 more answers

Can someone help me. All i need o know is what is the value after 10 years i done the equation part by myself

vazorg [7]

Answer:

$4811

Step-by-step explanation:

Initial price = 35,000

18% decrease anually = 18/100 = -0.18

after 10 years

substitute these values in the formula shown in below figure

A = 35000 * ( 1 + -0.18/1 ) ^10

= 35000 * 0.82^10

= 4,810.681

= $4811

7 0

2 years ago

A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

3 years ago