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nlexa [21]
3 years ago
7

Compare the time spent on each of the above operations, and describe your observations. If an operation is too fast, you may wan

t to repeat it for many times, i.e., 5000 times, and then take an average rsa aes
Computers and Technology
1 answer:
Artist 52 [7]3 years ago
3 0

Here's the complete question below that clarifies what you need to do

<u>Explanation</u>:

"In this task, we will study the performance of public-key algorithms. Please prepare a file ( message.txt) that contains a 16-byte message. Please also generate an 1024-bit RSA public/private key pair. Then, do the following:

1)Encrypt message.txt using the public key; save the the output in message_enc.txt.

2)Decrypt message_enc.txt using the private key.

3)Encrypt message.txt using a 128-bit AES key.

<em><u>Compare the time spent on each of the above operations, and describe your observations. If an operation is too fast, you may want to repeat it for many times, i.e., 5000 times, and then take an average.</u></em>

<em><u> After you finish the above exercise, you can now use OpenSSL's speed command to do such a benchmarking. Please describe whether your observations are similar to those from the outputs of the speed command?</u></em>

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What's the best item in the binding of isaac?
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Answer:

Spelunker Hat

Explanation:

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5 0
3 years ago
Encapsulation is the process of “packaging” information prior to transmitting it from one location to another. true or false
GenaCL600 [577]

The statement that encapsulation is the process of “packaging” information prior to transmitting it from one location to another is true.

This method augments the data with successive layers of control information before transmission across a network. Each OSI (Open System Interconnection) layer  is part of the encapsulation by adding a header to the data packet in the transmission network.

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3 years ago
Alice recently purchased a new cell phone. After her vacation, Alice wanted to transfer her holiday photos to her computer to do
dmitriy555 [2]

Answer:

<u>D.) Device Manager</u>

Explanation:

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5 0
3 years ago
The find_item functions uses binary search to recursively locate an item is the list, returning true if found, false otherwise.
bagirrra123 [75]

Answer:

def find_item(listed, item):

   listed.sort()

   #Returns True if the item is in the list, False if not.

   if len(listed) == 0:

       return False

   middle = int(len(listed)/2)

   #Is the item in the first half of the list?

   if item < listed[middle]:

   #Call the function with the first half of the list

       return find_item(listed[:middle], item)

   

   #Is the item in the center of the list?

   if listed[middle] == item:

       return True

   else:

   #Call the function with the second half of the list

       return find_item(listed[middle+1:], item)

   return False

list_of_names = ["Parker", "Drew", "Cameron", "Logan", "Alex", "Chris", "Terry", "Jamie", "Jordan", "Taylor"]

print(find_item(list_of_names, "Alex")) # True

print(find_item(list_of_names, "Andrew")) # False

print(find_item(list_of_names, "Drew")) # True

print(find_item(list_of_names, "Jared")) # False

Explanation:

The defined python function is used to implement a binary search, the function is recursively called in the function statement, but for it to work on the list ( ie, search for an item in the list), the list must be sorted in ascending order (default).

7 0
3 years ago
2.
Masja [62]

Answer:

is this a question or not?

6 0
3 years ago
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