Answer:
1/5
Step-by-step explanation:
up 1, right 5
Answer:
$25
Step-by-step explanation:
i have an odd method of solving these types of equations
25x=100
x=4
340/4 = 85
85 x 3 = 255
Answer:
I believe the answer is X=40
Step-by-step explanation:
cross multiply 5*16 = X * 2
Multiply 5*16
80= X*2
Add '-2x' to each side of the equation
80 + -2x = 2x + -2x
Combine like terms
80 + -2x = 0
Add '-80' to each side of the equation.
80 + -80 + -2x = 0 + -80
Combine like terms: 80 + -80 = 0
0 + -2x = 0 + -80
-2x = 0 + -80
Combine like terms: 0 + -80 = -80
-2x = -80
Divide each side by '-2'.
x = 40
Simplifying
x = 40
Hope this helped :)
Answer:

Step-by-step explanation:
Connect points I and K, K and M, M and I.
1. Find the area of triangles IJK, KLM and MNI:

2. Note that

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.