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Fed [463]
3 years ago
7

Which equation represents a linear function?

Mathematics
1 answer:
jeyben [28]3 years ago
3 0

Answer:

C

............................

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The neighborhood park has a rectangular shape. What is the perimeter of the park?​
Alenkinab [10]

Step-by-step explanation:

perimeter formula is adding up all the sides

so

5x-40 + 5x-40 + 3x-18 + 3x -18

= 16x -116

4 0
3 years ago
Consider the graph of the quadratic function y = 3x2 – 3x – 6. What are the solutions of the quadratic equation 0 = 3x2 − 3x − 6
son4ous [18]
Y = 3x^2 - 3x - 6 {the x^2 (x squared) makes it a quadratic formula, and I'm assuming this is what you meant...}

This is derived from:
y = ax^2 + bx + c

So, by using the 'sum and product' rule:

a × c = 3 × (-6) = -18

b = -3

Now, we find the 'sum' and the 'product' of these two numbers, where b is the 'sum' and a × c is the 'product':

The two numbers are: -6 and 3

Proof:

-6 × 3 = -18 {product}

-6 + 3 = -3 {sum}

Now, since a > 1, we divide a from the results

-6/a = -6/3 = -2

3/a = 3/3 = 1

We then implement these numbers into our equation:

(x - 2) × (x + 1) = 0 {derived from 3x^2 - 3x - 6 = 0}

To find x, we make x the subject of 0:

x - 2 = 0

OR

x + 1 = 0

Therefore:

x = 2

OR

x = -1

So the x-intercepts of the quadratic formula (or solutions to equation 3x^2 - 3x -6 = 0, to put it into your words) are 2 and -1.


We can check this by substituting the values for x:

Let's start with x = 2:

y = 3(2)^2 - 3(2) - 6
= 3(4) - 6 - 6
= 12 - 6 - 6
= 0 {so when x = 2, y = 0, which is correct}

For when x = -1:

y = 3(-1)^2 - 3(-1) - 6
= 3(1) + 3 - 6
= 3 + 3 - 6
= 0 {so when x = -1, y = 0, which is correct}
7 0
3 years ago
Read 2 more answers
PLS HELP ME ASAP FOR ALL 6!! (MUST SHOW WORK!!!) +LOTS LOTS OF POINTS!!!
Sedaia [141]
1. -4a-6=-12
add 6 to both sides
-4a-6+6=-12+6
-4a=-6
Divide by -4
a= \frac{6}{4} = 1 \frac{1}{2}

2. \frac{3}{5} z- \frac{1}{4} = \frac{17}{20}
add \frac{1}{4} to both sides but you will need to make a common denominator on the right
\frac{3}{5} z- \frac{1}{4} + \frac{1}{4} =  \frac{17}{20} +  \frac{5}{20}
\frac{3}{5}z=  \frac{11}{10}
Divide by \frac{3}{5} which means multiply by the <span>reciprocal</span>.
\frac{3}{5}* \frac{5}{3} z= \frac{11}{10} * \frac{5}{3}
z= \frac{55}{30} =1 \frac{5}{6}

3. 2 \frac{1}{2}(e-1 \frac{3}{4})=5 \frac{1}{2}
Distribute 
2 \frac{1}{2} e-4 \frac{3}{8} =5 \frac{1}{2}
Subtract
2 \frac{1}{2} e=1 \frac{1}{8}
Divide
e= \frac{9}{20}

4. 3w+7=20
Subtract
3w=13
Divide
w= \frac{13}{3} = 4 \frac{1}{3}

5. -.2p+.4=-1.2
Subtract
-.2p=-1.6
Divide
p=8

6. \frac{y}{4} - \frac{3}{5} = \frac{18}{20}
Add, made sure you change to common denominator first
\frac{y}{4} = 1 \frac{1}{4}
Multiply by 4
y=5

Hope that helps

5 0
3 years ago
Read 2 more answers
7th-grade math I WILL GIVE BRAINLIEST !
andriy [413]

Answer:

It includes it because with out it there will be no center and it wouldn't be right. And with out it ever equation wont be proportional

Step-by-step explanation:

I really hope this helps Im just saying what I think is the answer it is my fault if you get the answer wrong <3

6 0
3 years ago
Graph each equation. 5y=20x-30
aivan3 [116]
<u>5y</u> = <u>20x - 30</u>
 5          5
y = 4x - 6
5(4x - 6) = 20x - 30
5(4x) - 5(6) = 20x - 30
20x - 30 = 20x - 30
<u>       +30            +30     </u>              
       <u>20x</u> = <u>20x</u>
        20      20
           x = 1
         5y = 20(1) - 30
         5y = 20 - 30
         <u>5y</u> = -<u>10</u>
          5       5
           y = -2
     5(-2) = 20(1) - 30
       -10 = 20 - 30
       -10 = -10
    (x, y) = (1, -2)
7 0
3 years ago
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