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Olin [163]
3 years ago
11

1. For each problem, use the properties of inequalities to write a true inequality statement.

Mathematics
1 answer:
vlabodo [156]3 years ago
8 0

Part a) The true inequality statement is: -2>-5

Part b) The true inequality statement is: -4>-7

Part c) The true inequality is 6

Step-by-step explanation:

We are given the two integers are -2 and -5.

Part a)

Write a true inequality statement.

The true inequality statement is: -2>-5

Part b)

Subtract-2 from each side of the inequality. Write a true inequality statement.

Subtracting -2 from each side we get:

-2>-5\\-2-2>-5-2\\-4>-7

The true inequality statement is: -4>-7

Part c)

Multiply each number by-3. Write a true inequality statement.​

Multiplying -3 on both sides:

-2>-5\\-2*-3>-5*-3\\Multiplying\,\,-3\,\,will\,\,change\,\,the\,\,inequality\,\,sign\\6

The true inequality is 6

Keywords: Solving inequalities

Learn more about Solving inequalities at:

  • brainly.com/question/6703816
  • brainly.com/question/11788572
  • brainly.com/question/4192226

#learnwithBrainly

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Greatest common divisor of 60 and 792 using the prime factorization method
klio [65]

Answer:

12

Step-by-step explanation:

8 0
3 years ago
Which of the following could be used to calculate the area of a sector in the circle shown below
lara [203]

Answer:

Therefore the Last option is correct

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

Step-by-step explanation:

Given:

Radius = r = 8 in

θ = 42°

To Find:

Area of Sector = ?

Solution:

We know that

\textrm{Area of Sector}=\pi (Radius)^{2}\times \frac{\theta}{360}

Substituting the given values in the formula we get

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

Which is the required Answer.

Therefore the Last option is correct

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

8 0
2 years ago
When multiplying numbers in scientific notation you blank the coefficients and substract the exponents?
34kurt
For the sake of example, let's multiply the two numbers 2.3 \times 10^5 and 3.5 \times 10^7 together. Altogether, we have:

2.3\times10^5\times3.5\times10^7

Rearranging the expression, we can group the exponents and coefficients together:

2.3\times3.5\times10^5\times10^7

Multiplying each out, we notice that since 10^5 and 10^7 have the same base (10), multiplying them has the effect of adding their exponents, which leaves us with:

2.3\times3.5\times10^{5+7}=8.05\times10^{12}

The takeaway here is that multiplying two numbers in scientific notation together has the effect of multiplying its coefficients and <em>adding</em> its exponents.
8 0
3 years ago
Assume that all six outcomes of a six-sided number cube have the same probability. What is the theoretical probability of each r
Margarita [4]
Hey there! I am on the same one. :) I will help you out a little. 

<span>Assume that all six outcomes of a six-sided number cube have the same probability. What is the theoretical probability of each roll? 
• 1: 1/6
• 2: 2/6
• 3: 3/6
• 4: 4/6
• 5: 5/6
• 6: 6/6
</span>
<span>Using the uniform probability model you developed, what is the probability of rolling an even number? 
1/6 Roll a number cube 25 times. Record your results here. 

</span><span> <span><span> <span> <span>1st toss=</span>6</span> </span> <span> <span> <span>2nd toss=</span>4</span> </span> <span> <span> <span>3rd toss=</span>6</span> </span> <span> <span> <span>4th toss=</span>6</span> </span> <span> <span> <span>5th toss=</span>3</span> </span> <span> <span> <span>6th toss=</span>3</span> </span> <span> <span> <span>7th toss=</span>4</span> </span> <span> <span> <span>8th toss=</span>2</span> </span> <span> <span> <span>9th toss=</span>6</span> </span> <span> <span> <span>10th toss=</span>5</span> </span> <span> <span> <span>11th toss=</span>1</span> </span> <span> <span> <span>12th toss=</span>4</span> </span> <span> <span> <span>13th toss = </span>5</span> </span> <span> <span> <span>14th toss =</span>1</span> </span> <span> <span> <span>15th toss=</span>4</span> </span> <span> <span> <span>16th toss=</span>2</span> </span> <span> <span> <span>17th toss=</span>2</span> </span> <span> <span> <span>18th toss=</span>2</span> </span> <span> <span> <span>19th toss=</span>6</span> </span> <span> <span> <span>20th toss=</span>5</span> </span> <span> <span> <span>21st toss=</span>3</span> </span> <span> <span> <span>22nd toss=</span>4</span> </span> <span> <span> <span>23rd toss=</span>3</span> </span> <span> <span> <span>24th toss=</span>3</span> </span> <span> <span> 25 toss=5
How many results of 1 did you have? __2____________ How many results of 2 did you have? ____4__________ How many results of 3 did you have? ____5__________ How many results of 4 did you have? ______5________ How many results of 5 did you have? ______4________  How many results of 6 did you have? ______5________
Based on your data, what is the experimental probability of each roll?  <span> 1. 2/25 or 0.08 

2. 4/25 or 0.16

3. 5/25 or 0.24

4. 5/25 or 0.2

5.4/25 or 0.16
<span>
6. 5/25 or 0.2</span></span>Using the probability model based on observed frequencies, what is the probability of rolling an even number? 3/6 = ½ or 0.5
Was your experimental probability different than your theoretical probability? Why or why not? <span>It somewhat is! The denominator is 25 for the experimental probability, and 6 for the theoretical probability.</span><span>
</span><span>Have a lovely day! Cheerio. :) </span></span> </span> </span></span>
8 0
3 years ago
Read 2 more answers
A girl can run 6 2/3 metres in one second. How long will it take her to run 100 metres?
Crank

Answer:

15 seconds

Step-by-step explanation:

How did i get this answer? It is apparent that the girl is capable of running 6 2/3 metres per one second and she must run 100 metres.

First, let's convert 2/3 into a decimal so that it is easier to calculate later. 2/3=0.667 (you can also just do 2 divide by 3 and will end up with the same number)

Now our numbers are 6.667 and 100. Let's divide 100 by 6.667 which estimates to 15

7 0
2 years ago
Read 2 more answers
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