Question

Pls help! Solve the equation by using quadratic formula. -2x’2 + 4x = 5

Answer 1

Answer:

$x=\frac{2\pm i\sqrt{6}}{2}$

Step-by-step explanation:

$-2x^2+4x=5\\\\-2x^2+4x-5=0\\\\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\x=\frac{-4\pm\sqrt{(4)^2-4(-2)(-5)}}{2(-2)}\\\\x=\frac{-4\pm\sqrt{16-40}}{-4}\\\\x=\frac{-4\pm\sqrt{-24}}{-4}\\ \\x=\frac{-4\pm2i\sqrt{6}}{-4}\\ \\x=\frac{2\pm i\sqrt{6}}{2}$