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sveta [45]
2 years ago
7

An adult male alligator may weigh 300 pounds. A newly hatched alligator weighs only one ninth 1/9 pound. The adult weighs how ma

ny times the​ hatchling?
Mathematics
2 answers:
Galina-37 [17]2 years ago
7 0

You do 1/9*9*300 which you can probably do

k0ka [10]2 years ago
3 0
300 divided by 1/9 is the answer
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Two water tanks are shown. Tank a is a rectangular prism and tank b is a triangular prism. Tank a is filled with water.
olganol [36]

Answer:

6 meters

Step-by-step explanation:

i see it on the picture and yeah and i did the math

3 0
2 years ago
Kabul’s bookshop marks up all books by 40 percent of their cost. The overhead rate is 16 percent of the selling price. What is t
morpeh [17]

Answer:

The net profit rate on the book is 5.41

Step-by-step explanation:

Given as :

The marks up percentage of book = m = 40%

The overhead rate is 16% of selling price

The cost price of book = c.p = $18.10

Let The profit = $p

Let The selling price = s.p

<u>Now, According to question</u>

mark up percentage = \dfrac{s.p - c.p}{c.p}

I.e 40% =  \dfrac{s.p - 18.10}{18.10}

Or, \dfrac{40}{100} + 1 = \dfrac{s.p}{18.10}

Or, \dfrac{140}{100} =  \dfrac{s.p}{18.10}

Or, s. p = \dfrac{140\times 18.10}{100}

∴ s.p = $25.34

So, selling price of book = s.p = $25.34

Now, The overhead percentage = 16%

i.e overhead rate = \dfrac{\textrm estimated cost}{\textrm estimated total base unit}

Or, estimated cost = 16% × 25.34

I,e estimated cost = 0.16 × 25.34

∴ estimated cost = $4.05

Now,

Profit = selling price of book - estimated book cost

I.e p = $25.34 - $4.05

∴ p = $21.29

So, The profit rate% = \dfrac{\textrm profit}{\textrm estimated cost}

I.e The profit rate% = \dfrac{21.29}{4.05}

∴ profit rate %= 5.41

So, The profit rate = p = 5.41

Hence, The net profit rate on the book is 5.41  Answer

4 0
3 years ago
What is 8 1/2 / 11 as a mixed number or fraction
Anettt [7]

Answer: 17/22

Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
Y=-4x-10 for all prime numbers less than 15. What is the domain and range for this?
Bad White [126]
The\ prime\ numbers\ less\ than\ 15\ is\ domain:\\\\D=\{2;\ 3;\ 5;\ 7;\ 11;\ 13\}\\\\Range:\\\\f(2)=-4(2)-10=-18\\f(3)=-4(3)-10=-22\\f(5)=-4(5)-10=-30\\f(7)=-4(7)-10=-38\\f(11)=-4(11)-10=-54\\f(13)=-4(13)-10=-62\\\\Range:\{-18;-22;-30;-38;-54;-62\}
4 0
3 years ago
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