I looked it up and this is what it said
Least to greatest: 1.5 qt; 7 c; 64 fl oz
Answer:
yes , 33^2 + 56^2 = 65^2 and obtuse
Step-by-step explanation:
<h2><u>Question 3</u></h2>
make use of the Pythagoras theorem
which is :
c^2 = a^2 + b^2
where c is the hypotenuse.
now put the values in the equation
65^2 = 56^2 + 33 ^2
the answer is :
<u>yes , 33^2 + 56^2 = 65^2</u>
<u></u>
<h2><u>Question 4</u></h2>
<u />
note if :
c^2 = a^2 + b^2 ----------- right
c^2 < a^2 + b^2------------ acute
c^2 > a^2 + b^2------------- obtuse
hence :
16 + 30 > 38
therefore its : <u>obtuse </u>
Given:
Total amount = $10
Cost of loaf of bread = $3.25
Cost of cheese = $5.99 per pound
Each slice weights = 0.04 pounds.
To find:
The inequality for the number of slices that Paul can afford to buy.
Solution:
Let x be the number of slices that Paul can afford to buy.
Weight of on slice is 0.04 pounds. So, weight of x slices is 0.04x pound.
Cost of cheese = $5.99 per pound
So, total cost of cheese for x slices = $5.99 × 0.04x
Now, Paul has $10 to buy bread and cheese for sandwiches. Cost of loaf of bread is $3.25.



Divide both sides by 0.2396.


The maximum integer value of x is 28.
Therefore, the required inequity is
and 28 number of slices Paul can afford to buy.