Explanation:
A carbon radical is a reaction intermediate, which is produced during a free-radical reaction. These carbon radicals contain one unpaired electron on a carbon atom. Hence, these radicals are highly reactive in nature.
Answer:
2s² 2p⁵
There are seven valance electrons in fluorine.
Explanation:
The elements of group 17 are called halogens. These are six elements Fluorine, Chlorine, Bromine, Iodine, Astatine. Halogens are very reactive these elements can not be found free in nature. Their chemical properties are resemble greatly with each other.
Properties of fluorine:
1. it is yellow in color.
2. it is flammable gas.
3. it is highly corrosive.
4. fluorine has pungent smell.
5. its reactions with all other elements are very vigorous except neon, oxygen, krypton and helium.
Electronic configuration of fluorine:
F₉ = 1s² 2s² 2p⁵
Valance electrons in fluorine are 2s² 2p⁵.
Valance Orbital configuration:
2s² 2p⁵
There are seven valance electrons in fluorine.
Since the compound has 1.38 time that of oxygen gas at the same conditions of temperature and pressure, we have the relationship:
MW/MWoxygen = 1.38
MW = 44.16
Since there is water formed during the reaction, the formula of the compound must be:
XaHb
where a and b are the coefficients of each element.
If the compound reactions with oxygen forming water and an oxide of the element X, the combustion reaction must be:
XaHb + ((2a + (b/2))/2) O2 = a (XO2) + (b/2)(H2O)
Using dimensional analysis:
10 (1/44.16) (b/2 / 1) (18) = 16.3
Solving for b:
b = 8
The compound now is XaH8. Most probably, the compound is C3H8 since it has a molecular formula of 44 and it reacts with O2 to form water and CO2.
Umm well its particles are always moving and excited so they are not so close
3.815 that's the awnser......................................
