C4H10 is an alkane (propane to be precise)
The relative formula mass of a molecule of propane is
(12x4) + (1x10) = 58
because a carbon atom has an atomic weight of 12 and a hydrogen atom has an atomic weight of 1.
Answer:
Explanation:
1) Se escoge la cadena con el mayor número de átomos de carbono. 2) Cuando hay dos cadenas posibles con el mismo número de átomos de carbono, se elige la que contenga el mayor número de triples ligaduras posibles. ... El átomo de carbono con la triple valencia libre se numera como 1.
Remember that in this case pressure is equal to 1.00 atm and temperature is equal to 273.15K. So,
P
V
=
n
R
T
→
n
=
P
V
R
T
=
1.00
a
t
m
⋅
7.0
L
0.082
a
t
m
⋅
L
m
o
l
⋅
K
⋅
273.15
K
=
0.31
Since we know hydrogen's molar mass (
2.0
g
m
o
l
), we can determine the mass
m
H
2
=
n
⋅
m
o
l
a
r
.
m
a
s
s
=
0.31
m
o
l
e
s
⋅
2.0
g
m
o
l
=
0.62
g
If indeed you are dealing with STP, remember that, under these conditions, 1 mole of any ideal gas occupies
22.4
L
. So,
n
=
V
V
m
o
l
a
r
=
7.0
L
22.4
L
=
0.31
moles
And, once again,
m
=
0.31
⋅
2.0
=
0.6
Bitter taste (opposed to sour taste of acids)...
Slimy, or soapy feel on fingers (Slippery).....
Many bases react with acids and precipitate salts......
Strong bases may react violently with acids. An acid spill can be safely neutralised by using a mild base......
Bases turn red litmus paper blue.....
Bases are substances that contain metal oxides or hydroxides........
Bases which are soluble in water form alkalis (soluble bases)......
Answer:
A noble gas configuration of an atom consists of the elemental symbol of the last noble gas prior to that atom, followed by the configuration of the remaining electrons. So for sodium, we make the substitution of [Ne] for the 1s22s22p6 part of the configuration. Sodium's noble gas configuration becomes [Ne]3s1. That is the answer.
Explanation:
Brainliest Please.
