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Vlad [161]
3 years ago
5

Ca + H2OFe + HgCl2Ca + Se​

Chemistry
1 answer:
Nadusha1986 [10]3 years ago
3 0

Chemical reaction and equation

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What kind (ionic or covalent) bond is FeCl2 + Na2CO3? (iron (II) chloride + sodium carbonate).
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Answer:

corbonate

Explanation:

i think so. not sure

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2 years ago
What are complementary pigment colors?
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Answer:B

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omplementary colors are two opposing colors that can be found on the color wheel.

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To use the gas law constant R=0.0821 the unit for temp should be kelvin and the unit for pressure should be atmospheres True or
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It is crucial to match your units of Pressure, Volume, number of mole, and Temperature with the units of R. If you use the first value of R, which is 0.082057 L atm mol-1K-1, your unit for pressure must be atm, for volume must be liter, for temperature must be Kelvin.

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A fixed mass of gas has a volume of 92 cm cube and 3 degrees Celsius. What will be its volume at 18 degrees celsius if the press
8090 [49]

Answer:

94.8454

Explanation:

Let volume be V

Let Temperature be T

V1= 92

T1= 3C but to kelvin 273+3= 300K

V2= ?

T2= 18 C but to kelvin 18+273= 291

\frac{v1}{t1}  =  \frac{v2}{t2}

\frac{92}{300}  =  \frac{v2}{291}

v2 \times 300 = 92  \times 291

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3 0
2 years ago
How many moles in 3.69 x 10^30 molecules of carbon dioxide?
Sedaia [141]

0.612 \times 10^{7} \text { moles of } \mathrm{CO}_{2} are present in 3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}

<u>Explanation:</u>

It is known that each mole of an element is composed of avagadro's number of molecules. So if we need to determine, we need to divide the number of molecules with the avagadro's number.

So,

    1 mol of element =6.02 \times 10^{23} molecules of element

As here 3.69 \times 10^{30} molecules of carbon di oxide is given. So the moles in it will be

   No. of moles of carbon dioxide = \frac{3.69 \times 10^{30}}{6.02 \times 10^{23}}

    No. of moles = 0.612 \times 10^{7} moles of carbon dioxide.

Thus,

0.612 \times 10^{7} of carbon dioxide are present in 3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}.

4 0
2 years ago
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