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Zarrin [17]
3 years ago
7

A 11.630 g milk chocolate bar is found to contain 7.815 g of sugar.How many milligrams of sugar does the milk chocolate bar cont

ain?
Chemistry
2 answers:
tigry1 [53]3 years ago
6 0

Answer: 7815 mg

Explanation:

Mass is the amount of matter contained in a substance.

It can be measured in units of kilograms (kg), grams (g), milli grams (mg) etc;

These units are interconvertible.

As it is given,  11.630 g milk chocolate bar is found to contain 7.815 g of sugar

milligrams of sugar= ?

1 g= 1000 mg

7.815g=\frac{1000}{1}\times 7.815=7815mg

Thus milk chocolate bar contain 7815 mg of sugar.

zzz [600]3 years ago
4 0
3.815 that's the awnser......................................




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Find the linear function Cequals​f(F) that gives the reading on the Celsius temperature scale corresponding to a reading on the
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Answer:

C = (5/9) F - (160/9)

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Explanation:

We are looking for a linear function so we can write the following condition

Y = aX + b

Applying it to the exercise we got C = a F + b

Let's use the facts that C = 0 when F = 32 and C = 100 when F = 212

0 = 32 a + b            (1)

100 = 212 a + b       (2)

From (1) b = - 32 a , when we replace this in (2) we obtain a = (5/9)

and b = - (5/9)32 = - 160/9

Finally the linear function is C = (5/9) F - (160/9)

Both readings are equal at a Z number so

Z = (5/9) Z - 160/9

(4/9) Z = -160/9 and Z = - 40

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4 years ago
how is the arrangement of molecules in a dense object different than arrangement by molecule in a less dense object
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A compound is made of two or more different atoms joined together. which image would best fit
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How many moles of AgNO3 must react to form 0. 854 mol Ag? mol AgNO3.
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The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

The balanced chemical equation for the dissolution of silver nitrate has been:

\rm AgNO_3\;\rightarrow\;Ag^+\;+\;NO_3^-

The aqueous solution of silver nitrate has been dissociated into the constituent silver and nitrate ions.

In a balanced chemical equation, the coefficient has been equivalent to the moles of each reactant forming the moles of product.

From, the balanced equation,

\rm 1\;mol\;AgNO_3=1\;mol\;Ag

The given moles of Silver has been 0.854 mol. Thus, the moles of silver nitrate required has been given as:

\rm 1\;mol\;Ag^+=1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;\times\;1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;mol\;AgNO_3

The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

For more information about the moles produced, refer to the link:

brainly.com/question/10606802

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