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Zarrin [17]
3 years ago
7

A 11.630 g milk chocolate bar is found to contain 7.815 g of sugar.How many milligrams of sugar does the milk chocolate bar cont

ain?
Chemistry
2 answers:
tigry1 [53]3 years ago
6 0

Answer: 7815 mg

Explanation:

Mass is the amount of matter contained in a substance.

It can be measured in units of kilograms (kg), grams (g), milli grams (mg) etc;

These units are interconvertible.

As it is given,  11.630 g milk chocolate bar is found to contain 7.815 g of sugar

milligrams of sugar= ?

1 g= 1000 mg

7.815g=\frac{1000}{1}\times 7.815=7815mg

Thus milk chocolate bar contain 7815 mg of sugar.

zzz [600]3 years ago
4 0
3.815 that's the awnser......................................




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The bond between which two atoms has the greatest degree of polarity
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Answer:

By comparing  the bonds between C-H and O-H, the O-H bond has the greatest degree of polarity.

Explanation:

Based on bond electronegative values which is a measure of the ability of a atom in a chemical bond to pull the shared electrons closer to its self.

The electronegativity of an element characterizes the elements chemical reaction.

From the available bonds

Oxygen has an electronegativity value of 3.44 and Carbon 2.55, while  Hydrogen has an electronegativity value of  2.20

Therefore the bond between carbon and hydrogen is much less polar than between oxygen and hydrogen.

The bond between oxygen and hydrogen has the greatest polarity.

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Read 2 more answers
This question in the screenshot
Morgarella [4.7K]

Mass of hydrate + crucible = 47.29 g

Mass of anhydrous salt = 2.7 g

Molar mass of anhydrous salt CuSO4 = 159.5 g

Given,

mass of empty crucible = 42.45 g

mass of hydrate salt= 4.84 g

mass of crucible after first heating = 46.1 g

mass of crucible after second heating= 45.153 g

mass of crucible after third heating= 45.15 g

so, as per the question we need to find...

Mass of hydrate + crucible = ? g

Mass of anhydrous salt = ? g

Molar mass of anhydrous salt CuSO4 = ? g

∴Mass of hydrate + crucible = 42.45 + 4.48 = 47.29 g

The given salt is in hydrate form, to remove water from this molecule we need to perform heating .

So we are taking the substance into the crucible as it is in less quantity.

Here, we performed heating 3 times and note the weight after every heating.

After this, assume that the water is totally evaporated and the remaining salt is in anhydrous form,

∴ Mass of anhydrous salt = 45.15 - 42.45 = 2.7 g

To find the molar mass of anhydrous salt of CuSO4,

atomic weight of Cu = 63.5 g

atomic weight of S = 32 g

atomic weight of O =16 g

∴ molar mass of anhydrous salt of CuSO4 = 63.5 + 32 + (16 ×3)

                                                                   =159.5 gm

Learn more about molar mass here...

brainly.com/question/837939

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2 years ago
Mrs. Nogaki tested four black markers in rubbing alcohol and in water. Each filter paper had four evenly spaced dots. She found
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Answer:

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Explanation:

dependent viable = output

so it's the output of what happens after the input.

  • she put the marker in the water which is the independent variable, that's the input
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3 years ago
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