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devlian [24]
3 years ago
14

Can you please help me? Keep it a little basic. (no decimals) Thanks for the help!

Mathematics
2 answers:
m_a_m_a [10]3 years ago
8 0
1/2 divided by 1/6: keep, change, change
1/2 times 6/1 equals 6/2 which is simplified to 3.

3/2 divided by 1/8: keep, change, change
3/2 times 8/1 equals 24/2 which is simplified to 12

hope this answered your question! :)
Delvig [45]3 years ago
4 0
When you are dividing fractions you just flip the second fraction upside down and multiply the two fractions
So the first is
½ x 6/1 = 6/2 = 3

For the second you write them as improper fractions then do the same
So it is
3/2 / 1/8 = 3/2 x 8/1 = 24/2 = 12

So the answer to the first question is 3 and the second is 12
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X^1/4 +3 =0 -Solve the equation. Check your solutions
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Answer:

81

Step-by-step explanation:

subtract 3 from both sides->x^1/4=-3

set both sides to the power of 4-> x=(-3)^4

solve-> x=81

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Line CD contains points C(7, 4) and D(6, 1). Line JK is parallel to line CD. Which two points lie on line JK?
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From 6,1 to 7,4 
We can determine the slope of the line
rise/run
3/1=3

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3 years ago
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algol [13]
7 10 thousands is equal to 70 thousand
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3 years ago
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Given 3X=-15<br> Prove X =-5
BartSMP [9]

Answer:

X = -5

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3X=-15

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4 0
3 years ago
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The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0
3 years ago
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