Question

A pump is to lift 18.0 kg of water per minute through a height of 3.60 m. What output rating (in watts) should the pump motor have? (Write the unit watts as W.)

Answer 1

Answer:

$10.6$ W

Explanation:

m = mass of water being lited = 18.0 kg

t = time taken to lift the amount of water = 1 min  = 60 sec

g = acceleration due to gravity = 9.8 m/s²

h = height to which the amount of water is raised = 3.60 m

P = Power output of the pump

Power output of the pump to lift the water can be given as

$P = \frac{mgh}{t}$

Inserting the values

$P = \frac{(18) (9.8) (3.60)}{60}$

$P = 10.6$ W