Answer:
The P site
Explanation:
After the formation of peptide linkage, the trna of P site becomes free, more to the E site and then slip away. The A site trna has dipeptide instead of a single aminoacid.
In the prescence of translocase and energy from GTP, the ribosome move in such a way the peptidyl bearing trna of A site come to lie with P sit. This exposes next codon to A site. A new aminoacid trna complex reaches the fresh codon exposed at A site.
We will assume that the CM of the arm is at "L"
from the elbow, and the ball is at 34cm. Then the net torque is computed
by:
Net τ = 1.42 N * 34 cm + 1.50 kg * 9.8m/s² * 34 cm/2 – 12.6 N*2.75cm
= 48.28 N*cm + 1.50kg * 9.8m/s² * 34 cm/2 – 12.6 N*2.75cm
= 48.28 N*cm + 499.8 – 34.65 N*cm
τ = 513.43 N*cm or
5.1343 N*m
Answer: c)• 2/3
Explanation:
Lets say q1 and q2 are two charges with r distance far apart.
So electrostatic force
F = (k q1 q2) / r²
as k = Coulomb's constant
Now
q1' = 2q1
q2' = q2/3
Therefore the new electrostatic force
F' = (k q'1 q'2) / r²
F' = (k 2q1 q2) / 3r²
F' = 2/3 [(k q1 q2) / r²]
so F' = 2/3F
New electrostatic force is 2/3F
