All categories

2 years ago

A block slides down an incline plane that makes a 30 degree angle with the

Physics

1 answer:

Alona [7]2 years ago

7 0

Hi there!

We know that:

Force due to gravity = Mgsinθ

Force due to friction = μMgcosθ

Let the positive direction be directed in the direction of the block's acceleration, which is downward.

Thus:

ΣF = Mgsinθ - μMgcosθ

Solving for acceleration requires diving all terms by the mass, so:

a = gsinθ - μgcosθ

Substitute in given values. (g = 9.8 m/s²)

a = 9.8sin(30) - 0.3(9.8)cos(30) = 2.354 m/s²

You might be interested in

The acceleration of a particle is given by a = 6t - 28, where a is in meters per second squared and t is in seconds. Determine t

baherus [9]

Answer:

Velocity, V = 3t²- 28t+6

Displacement, s = t³ - 14t²+6t -8

At t = 5.8 s

s = -249.05 m

v = -55.48 m/s

At t = 12.7 s

s = -141.48 m

v = 134.27 m/s

Explanation:

We have acceleration of a particle is given by a = 6t - 28

Velocity

$v=\int adt=\int (6t - 28)dt=3t^2-28t+C$

At t = 0 we have v₀ = 6 m/s

v₀ = 6 = 3 x 0 ²-28 x 0+C

C = 6

So velocity, V = 3t² - 28t+6

Displacement

$s=\int vdt=\int (3t^2-28t+6)dt=t^3-14t^2+6t+C$

At t = 0 we have s₀ = -8 m

s₀ = -8 = 0³ + 14 x 0² + 6 x 0 + C

C = -8

So displacement, s = t³ - 14t²+6t -8

At t = 5.8 s

s = 5.8³ - 14 x 5.8²+6 x 5.8 - 8 = -249.05 m

v = 3 x 5.8² - 28 x 5.8 + 6 = -55.48 m/s

At t = 12.7 s

s = 12.7³ - 14 x 12.7²+6 x 12.7 - 8 = -141.48 m

v = 3 x 12.7² - 28 x 12.7 + 6 = 134.27 m/s

4 0

2 years ago

A space probe is traveling in outer space with a momentum that has a magnitude of 3.87 x 107 kg·m/s. A retrorocket is fired to s

Virty [35]

Force = change in momentum / time, Force in opposite direction so negative
-1.41 x 10⁶ = (p₂ - 3.87 x 10⁷) / 9.55
p₂ = 2.52 x 10⁷ Ns

6 0

3 years ago

If a stereo has a dial that changes the volume of the sounds the stereo makes, what is the dial doing? a. changing the number of

Over [174]

If the stereo has a dial that changes the volume of the sounds the stereo makes, the one that being done by the dial is : D. Changing the amplitude of the sound waves

Hope this helps

8 0

3 years ago

Read 2 more answers

A hungry 169169 kg lion running northward at 77.377.3 km/hr attacks and holds onto a 31.731.7 kg Thomson's gazelle running eastw

navik [9.2K]

Answer: 75,242.9 m/s

Explanation:

from the question we are given the following parameters

mass of Lion (ML) = 169,169 kg

velocity of lion (VL) = 777,377.7 m/s

mass of Gazelle (Mg) = 31,731.7 kg

velocity of Gazelle (Vg) = 63,863.8 kg

mass of Lion and Gazelle (M) = 200,900.7 kg

velocity of Lion and Gazelle (V) = ?

The first figure below shows the motion of the Lion and Gazelle with their direction.

The second diagram shows the motion of the Lion and Gazelle with their directions rearranged to form a right angle triangle.

from the triangle formed we can get the velocity of the Lion and Gazelle immediately after collision using their momentum and Phytaghoras theorem

momentum = mass x velocity

momentum of the Lion = 169,169 x 77,377.3 = 13,089,840,463.7 kgm/s

momentum of the Gazelle = 31,731.7 x 63,863.8 = 2,026,506,942.46 kgm/s

momentum of the Lion and Gazelle = 200,900.7 x V

now applying Phytaghoras theorem we have

13,089,840,463.7 + 2,026,506,942.46 = 200,900.7 x V

15,116,347,406.16 = 200,900.7 x V

V = 75,242.9 m/s

7 0

2 years ago

Read 2 more answers

Binding energy is the energy needed to

densk [106]

Answer:

Answer C

Explanation:

4 0

2 years ago