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mariarad [96]
4 years ago
14

.

Physics
1 answer:
Allushta [10]4 years ago
3 0

Answer:

UNIT ELASTIC

Explanation:

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Consider N non-interacting diatomic molecules stuck on a metal surface. Each molecule can either lie flat on the surface, in whi
Art [367]

Answer:

Detailed solution given in diagram

7 0
3 years ago
A huge block of stone has a mass of 650kg and gains 70000j of gpe. how high has it been raised? (g = 10m/s2 )
Anna35 [415]
The formula for calculating GPE is

GPE = m x h x g

Where m is mass, h is height raised and g is gravity.

To solve the problem we just have to substitute the values we are given

70,000J = 650 x 10 x y

70,000J = 6500 x y

70,000 / 6500 = y

10.769 = y

So, the block of stone has been raised approximately 10.769 metres.
5 0
2 years ago
The householder installs cavity wall insulation. What would happen to the time taken for the temperature to fall between points
scoundrel [369]

Answer:

the answers the correct one is: the time increases

Explanation:

When an insulating material is placed in the cavity of a wall the thermal conductivity of the system increases, therefore the temperature changes take longer.

             P= dQ / dt = K A dT / dx

when placing insulation the value of k is less

When reviewing the answers the correct one is: the time increases

5 0
4 years ago
A boat heads directly across a river. Its speed relative to the water is 2.6 m/s. It takes it 355 seconds to cross, but it ends
Zigmanuir [339]

Answer:

Vr = 3.24m/s

The boat is going 3.24m/s relative to the bank of the river.

Explanation:

The relative speed of the boat to the bank Vr is the resultant of speed of boat relative to the water Vb and the speed of boat as a result of the water current or wind Vw

Vr = √(Vb^2 + Vw^2) .....1

Given;

Vb = 2.6m/s

Vw = distance downstream/time = 690m/355s

Vw = 1.94m/s

From equation 1 above; substituting the values

Vr = √(2.6^2 + 1.94^2)

Vr = 3.24m/s

The boat is going 3.24m/s relative to the bank of the river.

7 0
3 years ago
When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq
Sindrei [870]

Answer:

<h2> 0.041kg</h2>

Explanation:

Step one:

given data

initial velocity u= 0m/s

Force F= 443N

time t= 4.3 ms= 0.0043seconds

final velocity v= 45.7m/s

Step two:

Required

mass m

we know that the expression for impulse is given as

Ft=mv

make m subject of the formula

m=Ft/v

substitute we have

m=443*0.0043/45.7

m=1.90/45.7

m=0.04kg

The mass of the ball is 0.041kg

6 0
3 years ago
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