If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
Step-by-step explanation:
1/2(6x+1/2)=0
3x+1/4=0
3X=-1/4
X=3(-1/4)
X=-3/4
OR
X=-.75
Answer:
This equation has 2 solutions.
1. 
2. 
Answer:
62
Step-by-step explanation:

Answer:
we need more information
Step-by-step explanation: