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Tresset [83]
3 years ago
12

1 to the tenth power

Mathematics
2 answers:
dmitriy555 [2]3 years ago
8 0
Answer: 1

Explanation:

1 to any power will always be 1
Nuetrik [128]3 years ago
7 0

Answer:

1

Step-by-step explanation:

1 to the tenth power is also 1 multiplied by 1 10 times.

1 · 1 · 1 · 1 · 1 · 1 · 1 · 1 · 1 · 1 = 1

1 to any power will always have the answer of 1.

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The length of a desk is 3.5 feet. How many centimeters is the length? (There are 2.54 cm in an inch)
gregori [183]

Answer:106.

Step-by-step explanation:

5 0
3 years ago
Using the function f(x) = -3 x -5, calculate f(-7)
KonstantinChe [14]
Answer: X=16

Explanation: when you plug in -7 for x in the equation you have and just multiply it by -3 you will get 21 then subtract 5 and that will give yo 16
7 0
2 years ago
Please answer with process
laila [671]

\mathsf{Given : a - b = 5}

\mathsf{Squaring\;on\;both\;sides,\;we\;get :}

\mathsf{\implies (a - b)^2 = 5^2}

\mathsf{\implies a^2 + b^2 - 2(a.b) = 25}

\mathsf{Given : a^2 + b^2 = 29}

\mathsf{\implies 29 - 2(a.b) = 25}

\mathsf{\implies 2(a.b) = 29 - 25}

\mathsf{\implies 2(a.b) = 4}

\mathsf{\implies (a.b) = 2}

6 0
3 years ago
Can you please help me out with a question
kozerog [31]

As you can see in the given figure, there are two intersecting chords inside the circle.

Recall that the "Intersecting Chords Theorem" is given by

AE\cdot EC=BE\cdot DE

For the given case, we have

AE = 7

BE = 6

EC = 9

Let us substitute these values into the above equation and solve for DE

\begin{gathered} AE\cdot EC=BE\cdot DE \\ 7\cdot9=6\cdot DE \\ 63=6\cdot DE \\ \frac{63}{6}=DE \\ 10.5=DE \\ DE=10.5 \end{gathered}

Therefore, the length of DE is 10.5 units.

8 0
1 year ago
An airplane climbs 100 feet during the first second after takeoff. In each succeeding second it climbs 100 feet more than it cli
tigry1 [53]

Answer:

15 seconds.

Step-by-step explanation:

∵ The distance covered by plane in first second = 100 ft,

Also, in each succeeding second it climbs 100 feet more than it climbed during the previous second,

So, distance covered in second second = 200,

In third second = 300,

In fourth second = 400,

............, so on....

Thus, the total distance covered by plane in n seconds = 100 + 200 + 300 +400......... upto n seconds

=\frac{n}{2}(2\times 100 + (n-1)100)  ( Sum of AP )

=\frac{n}{2}(200+100n-100)

=\frac{n}{2}(100+100n)

=50n+50n^2

Suppose the distance covered in n seconds is 12,000 feet,

\implies 50n+50n^2=12000

n+n^2=240

n^2+n-240=0

n^2+16n-15n-240=0

n(n+16)-15(n+16)=0

(n-15)(n+16)=0

\implies n=15\text{ or }n=-16

∵ n can not be negative,

Hence, after 15 seconds the plane will reach an altitude of 12,000 feet above its takeoff height.

6 0
3 years ago
Read 2 more answers
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