Jon is selling tickets for the school talent show. On the 1st day, he sold 3 senior tickets and 12 child tickets for $195. On th
1 answer:
<h3>Question:</h3>
<em>Jon is selling tickets for the school talent show. On the 1st day, he sold 3 senior tickets and 12 child tickets for $195. On the 2nd day he sold 13 senior tickets for $299. Find the price of a senior citizen ticket.</em>
<h3>Answer:</h3>- $23
Create a system of equations to help you solve this problem. The system of equations will look like: 3s + 12c = 195 and 13s = 299. The variable s represents the cost of senior tickets and the variable c represents the cost of children tickets.
Solve the second equation for the variable s as this is the easiest way to solve the problem. Solve the second equation for s by dividing both sides of the equation by 13 to isolate the variable s.
s = 23
Since the question was only asking for the price of a senior citizen ticket, you are technically done. The first equation was only put there to confuse you or allow you to check your work if you needed to. The price of a senior citizen ticket (variable s) is $23.
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Answer:
Option B can be quadratic.
Step-by-step explanation:
Take a look at the data.
A quadratic equation is of the form ,
,
where, a,b,c are constants.
<em>To find an unknown equation of 3 variables,</em>
<em>we need 3 points lying on the equation.</em>
here they have given, 5 points, meaning all should lie on the curve.
<em>For first option,</em> inserting first 3 points to find equation, we get equation as,
, but the rest points don't satisfy the curve.
So first option is not quadratic.
Similarly, it can be shown that option C and D are also not quadratic.
While, in option B, it is clear that for every y, x is y squared,
, thus quadratic in nature.