Answer:
A., B. & C.
Explanation:
All apply, because all these happen in a plant.
Answer:
29.75 revolutions
Explanation:
The kinematic formula for distance, given a uniform acceleration a and an initial velocity v₀, is

This car is starting from rest, so v₀ = 0 m/s. Additionally, we have a = 9.2/9.7 m/s² and t = 9.7 s. Plugging these values into our equation:

So, the car has travelled 44.62 m in 9.7 seconds - we want to know how many of the tire's <em>circumferences</em> fit into that distance, so we'll first have to calculate that circumference. The formula for the circumference of a circle given its diameter is
, which in this case is 47.8π cm, or, using π ≈ 3.14, 47.8(3.14) = 150.092 cm.
Before we divide the distance travelled by the circumference, we need to make sure we're using the same units. 1 m = 100 cm, so 105.092 cm ≈ 1.5 m. Dividing 44.62 m by this value, we find the number of revs is
revolutions
Answer:
94.28 cm
Explanation:
The formula for elastic potential energy is given as;
PEel = 1/2 *k*x² where x is the displacement, k is the spring constant
Given
PEel = 110 J, k= 350 N/m then find x
PEel = 1/2 *k*x²
110 = 1/2 * 350 * x²
110 = 175 x²
110/175 = x²
0.6286=x²
√0.6286 =x
0.7928 m = x
79.28 cm = x
New length of spring = 15 cm + 79.28 cm = 94.28 cm