It would take you approximately an hour and 15 mins
Answer:
<h2>The coefficient of static friction will be
0.7</h2>
Explanation:
Given data
the radius of curve= 90m
speed v= 90 km/h to m/s = (90*100)/60*60= 25 m/s
we know that the expression for the centripetal force acting on the car
-------1
we also know that the expression for the frictional force between road and tire.
Ff= μmg--------2
Equating equation 1 and 2 we have
μmg= mv^2/r
μ= v^2/gr
substituting the values of speed and radius we have (assuming g= 9.81m/s^2)
μ= 25^2/9.81*90
μ= 625/882.9
μ= 0.7
To solve the problem, we can use Charle's law, which states that for an ideal gas at constant pressure the ratio between absolute temperature T and volume V remains constant:

For a gas transformation, this law can be rewritten as

(1)
where 1 and 2 label the initial and final conditions of the gas.
Before applying the law, we must convert the temperatures in Kelvin:


The initial volume of the gas is

, so if we re-arrange (1) we find the new volume of the gas:
The net force of the car is greater than zero in the horizontal direction. If it were not greater thn zero, then the vehicle would remain stationary.