Question

Q C During a solar eclipse, the Moon, the Earth, and the Sun all lie on the same line, with the Moon between the Earth and the Sun. (c) What force is exerted by the Sun on the Earth?

Answer 1

The force exerted by the Sun on the Earth is $=3.557 \times 10^{22}$

What is the Netwon law of the gravity state?

Newton's law of gravity states that the force executed by a body on another body is calculated

$F=\frac{G \cdot m_1 \cdot m_2}{d^2}$

What is universal gravitation?

The universal gravitation constant

$G=6 \cdot 67 \times 10^{-11} \cdot \mathrm{m}^3 \cdot 8^{-2} \cdot \mathrm{kg}^{-1}$

Here we know that

The mass of the sun is $m_s=2.0 \times 10^{30} \mathrm{~kg}$ is the

The mass of the moon is $m_M=7.3 \times 10^{22} \mathrm{~kg}$

The mass of the Earth is $m_E=6.0 \times 10^{24} \mathrm{kg}$

The distance between the Sun and the Earth is

$d_{S E}=1.5 \times 10^{11} \mathrm{~m}$

The distance between the earth and the moon is

$d_{E M}=3.85 \times 10^8 \mathrm{~m} \text {. }$

Here the calculation is:

$F_{S E}=\frac{G \cdot m_S \cdot m_E}{\left(d_{S E}\right)^2}$

$=\frac{6.67 \times 10^{-11} \times 2.0 \times 10^{30} \times 6.0 \times 10^{24}}{\left(1.5 \times 10^{11}\right)^2}$

$=\frac{80.04 \times 10^{43}}{1.5^2 \times 10^{22}}=\frac{80.04 \times 10^{21}}{2.25}$

$=3.557 \times 10^{22}$

To learn more about quadratic equations, refer: brainly.com/question/21570007

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