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trapecia [35]
3 years ago
8

The mean age of Lincoln's tee-ball team is 5. Suppose one of his 7-year-old teammates quits the team, but a 6-year-old joins the

team. Is the mean age of Lincoln's team still 5? Explain your reasoning.
Mathematics
2 answers:
Shkiper50 [21]3 years ago
8 0

Answer:

no  it is not

Step-by-step explanation:

because it is out of that range

aleksandrvk [35]3 years ago
6 0

Answer:

Depending on the amount of children in the tee ball team, the mean may be lowered drastically or minorly. However, the mean would no longer be 5, although it may round up to five, if it is a decimal.

Step-by-step explanation:

Hope that helps, I didn’t do a very good job of explaining that question. But the answer is no.

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a football match,the ratio of children to adults is 2:7.there are 2700 people int he crowd. each adult ticket is £8 each child t
marusya05 [52]

Step-by-step explanation:

since the ratio of children to adult is 2:7,

2+7 = 9

number of children would be

(2 × 2700)/9 = 600 children in the crowd

number of adults would be

(7 × 2700)/9 = 2100 adults in the crowd

So, if a ticket costs £8 per adults, total cash made from adult

= 8 × 2100 = £16800

if a ticket costs £(8 - 3) per children, total cash made from children

= 5 × 600 = £3000

total money made = £(16800 + 3000)

= £19800

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3 years ago
Which type of function correctly describes the exponential function
Dennis_Churaev [7]

the answer is a. increasing function

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4 years ago
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Answer:

It may be 71.78 cm square

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3 years ago
The sum of two numbers is 82 and their difference is 26. find each of the numbers.
Zarrin [17]
54 because if x+y=82 and x-y=26 add 26 and 82 is 108 the divide it by 2 your answer is 54
7 0
4 years ago
Read 2 more answers
I need the answers plz
garik1379 [7]

Answer:

These problems are an example of equations with two unknowns. The way these equations are solved is that we write these equations one under the another.

If both equations have, such is the case here, same parts, we can simply cancel the same parts out and subtract the rest of equatuons. That way, we are left with only one unknown (the other one was eliminated), which makes it easy to solve.

After we have found the value of an unknown, we just plug it back into any of the starting equations and solve for the second unknown.

2. Adult ticket costs $12 and child ticket costs $14.

3. Adult ticket costs $10 and child ticket costs $5.

4. One daylily costs $9 and one bush of ornamental grass costs $2.

5. A van can carry 15 and a bus can carry 56 students.

Step-by-step explanation:

2. If we mark the price of one adult ticket with x and the price of one child ticket with y, we get that:

- first day: 7x + 12y = $252

- second day: 7x + 10y = $224

Now, we can make a system:

7x + 12y = 252

7x + 10y = 224

We can now subtract these two equations and 7x will cancel out, so we get:

12y - 10y = 252 - 224

2y = 28

y = 14

Now, we can plug the value of y into any of the two equations:

7x + 10y = 224

7x + 140 = 224

7x = 84

x = 12

3. Similarly, if we mark the price of one adult ticket with x and the price of one child tickey with y, we'll get a system:

x + 12y = 70

x + 9y = 55

Again, if we subtract these two, x will cancel out, so we have:

12y - 9y = 70 - 55

3y = 15

y = 5

Now, we plug the value of y into any of the two equations, and we get:

x + 9y = 55

x + 45 = 55

x = 10

4. Using the same principle, we can mark the price of one daylily with x and the price of one bunch of ornamental grass with y, we'll get a system:

12x + 11y = 130

12x + 12y = 132

Again, we subtract so that 12x cancel out and we get:

11y - 12y = 130 - 132

-y = -2

If we get minuses on both sides, we can simply multiply both sides with -1 and we get:

y = 2

Again, we plug y:

12x + 12y = 132

12x + 24 = 132

12x = 108

x = 9

5. If we mark number of students in a van with x and the number of students in a bus with y, we get a system:

2x + 12y = 702

2x + y = 86

As you've probably already noticed the pattern, we subtract equations and cancel 2x out to get:

12y - y = 702 - 86

11y = 616

y = 56

Once again, we plug the value of y into any equation:

2x + y = 86

2x + 56 = 86

2x = 30

x = 15

4 0
3 years ago
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