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AnnyKZ [126]
3 years ago
15

A person earns $187.42 before deductions for 3 days work . What is the rate of per hour assuming 8 hours of work per day ?

Mathematics
1 answer:
Bingel [31]3 years ago
6 0
7.809125 dollars per hour

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How do I solve this?? pic attached
lisov135 [29]

Answer:

y=-⅓x+7

Step-by-step explanation:

Since the new line we need to make must be parallel to the old one the number changing x must stay the same. this means that that we will still have -⅓ X. Now that we have part of the line formula, we can try to fit it to the point. Because the X is equal to 9, -1/3*9 is -3. To get it to the correct point, we have to add 7, so that our Y is 4. If we combine the two parts of the equation, we get Y=-⅓x+7

8 0
3 years ago
Four types of energy?
ohaa [14]
<span>Potential Energy is any type of stored energy. It can be chemical, nuclear, gravitational, or mechanical.Kinetic  ...GRAVITATIONAL.CHEMICAL.<span>NUCLEAR.
even motion.</span></span>
3 0
3 years ago
Read 2 more answers
Rafael counted a total of 40 white cars and yellow.There were 9 times as many white cars as yellow cars how many white cars did
Naily [24]
Well 9x40 would be the solution, so what is 9x40? That will be your answer.
6 0
3 years ago
Simply. If the solution is not a real number enter not a real number rotate picture answer all 3 please
yuradex [85]

Answer:

13. \frac{\sqrt[5]{x^4} }{x}.

14. v = \pm3\sqrt{5}

15. 2.

Step-by-step explanation:

13. x^{1/5} * x^{-2/5}

= x^{1/5 + (-2/5)}

= x^{1/5 - 2/5}

= x^{-1/5}

= \frac{1}{x^{1/5}}

= \frac{x^{4/5}}{x^{1/5 + 4/5}}

= \frac{x^{4/5}}{x}

= \frac{\sqrt[5]{x^4} }{x}.

14. v^2 - 45 = 0

v^2 = 45

\sqrt{v^2} = \pm\sqrt{45}

\sqrt{v^2} = \pm\sqrt{3^2 * 5}

v = \pm3\sqrt{5}.

15. \sqrt[3]{2} * \sqrt[3]{4}

= \sqrt[3]{2 * 4}

= \sqrt[3]{2 * 2 * 2}

= \sqrt[3]{2 ^3}

= 2.

Hope this helps!

7 0
3 years ago
SAT verbal scores are normally distributed with a mean of 433 and a standard deviation of 90. Use the Empirical Rule to determin
laila [671]

34% of the scores lie between 433 and 523.

Solution:

Given data:

Mean (μ) = 433

Standard deviation (σ) = 90

<u>Empirical rule to determine the percent:</u>

(1) About 68% of all the values lie within 1 standard deviation of the mean.

(2) About 95% of all the values lie within 2 standard deviations of the mean.

(3) About 99.7% of all the values lie within 3 standard deviations of the mean.

$Z(X)=\frac{x-\mu}{\sigma}

$Z(433)=\frac{433-\ 433}{90}=0

$Z(523)=\frac{523-\ 433}{90}=1

Z lies between o and 1.

P(433 < x < 523) = P(0 < Z < 1)

μ = 433 and μ + σ = 433 + 90 = 523

Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.

i. e. ((\mu-\sigma) \ \text{to} \ (\mu+\sigma))=68\%

Here μ to μ + σ = \frac{68\%}{2} =34\%

Hence 34% of the scores lie between 433 and 523.

8 0
3 years ago
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