The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.
<h3>Electric field on the master charge</h3>
E = kq/r²
where;
- q is magnitude of master charge
- r is distance of separation
- k is Coulomb's constant
E = (9 x 10⁹ x 0.63)/(0.75²)
E = 1.008 x 10¹⁰ N/C
<h3>Force on the test charge</h3>
F = Eq
where;
- E is electric field
- q is the test charge
F = (1.008 x 10¹⁰) x (0.5)
F = 5.04 x 10⁹ N
Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.
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Answer:
0.04 mm Hg / mL / min .
Explanation:
Arterial pressure = 120 mm Hg
right atrial pressure = 0 mm Hg
Drop in pressure due to peripheral resistance = 120 mm Hg
volume of cardiac output per minute = 3000 mL/min
total peripheral resistance
= 120 / 3000 mm Hg / mL / min
= 0.04 mm Hg / mL / min .
Mass= density x volume
1.3 kg/m^3 x ( 2.5x4x10) m^3
= 130 kg
Given parameters:
Mass of object = 6.7kg
Velocity = 8m/s
Unknown parameter:
Kinetic energy = ?
Energy is defined as the ability to do work. There are two forms of energy;
Kinetic and potential energy.
Kinetic energy is the energy due to the motion of a body. Whereas, potential energy is the energy due to the position of a body usually at rest.
Kinetic energy is mathematically expressed as;
Kinetic energy = 
where m is the mass of the body
v is the velocity of the body
Since we have been given both mass and velocity, input the parameter to solve for the unknown;
Kinetic energy = 
x 6.7 x 8² = 214.4J
So the kinetic energy of the body is 214.4J
