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Vedmedyk [2.9K]
3 years ago
12

Apply the kinetic theory to describe the motion of particles in a homogenous mixture of sugar and water as it is boiled.

Physics
2 answers:
Ivahew [28]3 years ago
8 0

Answer:

Evaporation

Explanation:

- The sugar molecules are more massive than the water (H2O) molecules. This can be compared across using their Molecular mass (Mr). Since, sugar molecules are more massive they are slower than water (H2O) molecules.

- As Heat is transferred to the the solution the temperature of the mixture rises that increases the speed of all molecules inside the mixture. ( Boltzman expression).

- As the speed of the molecules of water is relatively faster than those of sugar molecules, the molecules of water start to break free from their bonds of liquid and escape into the atmosphere ( evaporation) as gaseous molecules ( steam ).

nekit [7.7K]3 years ago
7 0

Answer:

Water turns into vapor leaving sugar behing.

Explanation:

During the kinetic theory of motion of particles during the boiling of a homogeneous mixture of sugar and water, molecules starts moving faster because of the sudden increase in temperature, making the molecules to spread further apart from each other. As sugar water is been heated the water will suddenly turn into vapor leaving the sugar behind.

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What is a substance ?????
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Substance is some matter (it can be solid liquid or gas) that has its own properties.. everything in this world are substances...
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6 0
3 years ago
A 1400.0 kg car crests a 3200.0 m pass in the mountains and briefly comes to rest. The car descends 1000 m before climbing and c
rjkz [21]

Answer:

a) v = 88.54 m/s

b) vf = 26.4 m/s

Explanation:

Given that;

m = 1400.0 kg

a)

by using the energy conservation

loss in potential energy is equal to gain in kinetic energy

mg × ( 3200-2800) = 1/2 ×m×v²

so

1400 × 9.8 × 400 = 0.5 × 1400 × v²

5488000 = 700v²

v² = 5488000 / 700

v² = 7840

v = √7840

v = 88.54 m/s

b)

Work done by all forces is equal to change in KE

W_gravity + W_non - conservative = 1/2×m×(vf² - vi²)

we substitute

1400 × 9.8 × ( 3200-2800) - (5 × 10⁶) = 1/2 × 1400 × (vf²  -0 )

488000 = 700 vf²

vf² = 488000 / 700

vf² = 697.1428

vf = √697.1428

vf = 26.4 m/s

4 0
3 years ago
Alexis is studying how lenses work. She looks through a
Kryger [21]
It would be the 3rd one
6 0
3 years ago
An automobile rounds a curve of radius 50.0 m on a flat road.
bixtya [17]

Answer:

14m/s

Explanation:

Given parameters:

Radius of the curve  = 50m

Centripetal acceleration  = 3.92m/s²

Unknown:

Speed needed to keep the car on the curve = ?

Solution:

The centripetal acceleration is the inwardly directly acceleration needed to keep a body along a curved path.

 It is given as;

      a = \frac{v^{2} }{r}  

a is the centripetal acceleration

v is the speed

r is the radius

  Now insert the parameters and find v;

         v²   = ar

        v² = 3.92 x 50  = 196

         v  = √196 = 14m/s

6 0
3 years ago
Mass (kg)
Tju [1.3M]

Mass.

Because mass doesn't depend on weight but weight depends on mass.

8 0
3 years ago
Read 2 more answers
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