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Vedmedyk [2.9K]
3 years ago
12

Apply the kinetic theory to describe the motion of particles in a homogenous mixture of sugar and water as it is boiled.

Physics
2 answers:
Ivahew [28]3 years ago
8 0

Answer:

Evaporation

Explanation:

- The sugar molecules are more massive than the water (H2O) molecules. This can be compared across using their Molecular mass (Mr). Since, sugar molecules are more massive they are slower than water (H2O) molecules.

- As Heat is transferred to the the solution the temperature of the mixture rises that increases the speed of all molecules inside the mixture. ( Boltzman expression).

- As the speed of the molecules of water is relatively faster than those of sugar molecules, the molecules of water start to break free from their bonds of liquid and escape into the atmosphere ( evaporation) as gaseous molecules ( steam ).

nekit [7.7K]3 years ago
7 0

Answer:

Water turns into vapor leaving sugar behing.

Explanation:

During the kinetic theory of motion of particles during the boiling of a homogeneous mixture of sugar and water, molecules starts moving faster because of the sudden increase in temperature, making the molecules to spread further apart from each other. As sugar water is been heated the water will suddenly turn into vapor leaving the sugar behind.

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How much can having a lighted candle increase the temperature inside the shelter?
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3 years ago
Assume the radius of an atom, which can be represented as a hard sphere, is r = 1.95 Å. The atom is placed in a (a) simple cubic
Nuetrik [128]

Answer:

(a) A = 3.90 \AA

(b) A = 4.50 \AA

(c) A = 5.51 \AA

(d) A = 9.02 \AA

Solution:

As per the question:

Radius of atom, r = 1.95 \AA = 1.95\times 10^{- 10} m

Now,

(a) For a simple cubic lattice, lattice constant A:

A = 2r

A = 2\times 1.95 = 3.90 \AA

(b) For body centered cubic lattice:

A = \frac{4}{\sqrt{3}}r

A = \frac{4}{\sqrt{3}}\times 1.95 = 4.50 \AA

(c) For face centered cubic lattice:

A = 2{\sqrt{2}}r

A = 2{\sqrt{2}}\times 1.95 = 5.51 \AA

(d) For diamond lattice:

A = 2\times \frac{4}{\sqrt{3}}r

A = 2\times \frac{4}{\sqrt{3}}\times 1.95 = 9.02 \AA

6 0
3 years ago
Calculate the kinetic energy in joules of a 1200 kg automobile moving at 18 m/s .
vodka [1.7K]

Answer:

194,400 joules of kinetic energy.

Explanation:

Remember that to calculate the Kinetic energy you need to use the next formula:

Ke=\frac{1}{2}Mass*Velocity^2

We know that Mass= 1200 kg and velocity is 18m/s, so we insert those values into the formula:

Ke=\frac{1}{2}Mass*Velocity^2\\Ke=\frac{1}{2}1200kg*(18m/s)^2\\Ke=194,400 joules

So the kinetic energy of a car moving at 18m/s with a mass of 1200 kg would be 194,400 joules.

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3 years ago
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The strength of these forces depends on the masses of the Earth and me. If the strength just tripled, that means that at least one of us just picked up a lot more mass. If the Earth suddenly became three times as massive, then the weight of everything and everybody on it would suddenly triple, and I'm pretty sure it would be the end of all of us before too long.

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