Answer:
y = 6x² -13x -5
Step-by-step explanation:
(1,-12) (2,-7) (5,80)
y = ax² + bx + c
-12 = a*1² + b*1 + c = a+b+c (1)
-7 = 4a + 2b + c (2)
80 = 25a + 5b + c (3)
(2)-(1): 3a + b = 5 (4)
(3)-(2): 21a + 3b = 87 (5)
(4)*3: 9a + 3b = 15 (6)
(5)-(6): 12a = 72 a = 6
(4) b = -13
(2) c = -5
Answer:
3
Step-by-step explanation:
f(x) = 3x+1
f(x+h) = 3(x+h)+1 = 3x+3h+1
f(x+h) - f(x)= 3x+3h+1-3x-1 = 3h
3h/h=3
Answer:
q8h dosage = 112.5mg
Step-by-step explanation:
Given
Child Weight = 22.5 kg
Daily Intravenous Dosage = 40mg/kg
Type of Dose = q8h
Required
Calculate the q8h per dose
We start by calculating the total daily dosage in mg
This is calculated by multiplying the child weight by the intravenous dosage
Daily Dosage = 22.5kg * 40mg/kg
Daily Dosage = 900mg
This implies that the body weight requires 900 mg daily
Next is to calculate the q8h dosage
q8h means every 8 hours.
q8h dosage = 900mg/8
q8h dosage = 112.5mg
Answer: (3,2)
Step-by-step explanation:
For this set of system of equations, let's use elimination method to find x and y. Let's eliminate y first. In order to do so, the y values have to be the same. Therefore, you multiply the top equation by 3 and the bottom equation by 4.
9x+12y=51
-16x-12y=-72
Now, we can add the 2 equations together for the y to cancel out.
-7x=-21
x=3
Since we know x, we can plug it into any of the equations to find y.
3(3)+4y=17
9+4y=17
4y=8
y=2
With out x and y value, we can put them into an ordered pair. (3,2)
