Answer:
The cost of 1 pound meat is $ 4.5 And cost of 1 pound of cheese is $ 2.5.
Step-by-step explanation:
Let the cost of 1 pound of meat be x
Let the cost of 1 pound of cheese be y
Cost of 4 pounds of meat = 4x
Cost of 5 pounds of cheese = 5y
Since we are given that one customer purchases 4 pounds of meat and 5 pounds of cheese for a total of $30.50.
So, equation becomes :
Cost of 11 pounds of meat = 11x
Cost of 14 pounds of cheese = 14y
Since we are given that a sandwich shop owner comes in and purchases 11 pounds of meat and 14 pounds of cheese for $84.50.
So, equation becomes :
Thus the system of equations are :
-1 (Red line)
-2 (Black line)
Solving these equations graphically we get the solution
x = $4.5
y = $2.5
Hence The cost of 1 pound meat is $ 4.5 And cost of 1 pound of cheese is $ 2.5.
X=-.25,-.5,-1,1,.5,.25
y=1,2,4,-4,-2,-1
The answer is A it is correct.
Answer:
The first one: 19/15a
second one: b²-4ac = D
Step-by-step explanation:
for first one: take LCM and solve
for second one: you square the expression on both sides then b²= D + 4ac, then when you take 4ac to the left hand side, it becomes b²-4ac= D
N₁*$0.10 + n₂*$0.25 = $2.25
n₁ + n₂ = 12
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This means that:
n₁ = 12 - n₂
And:
(12 - n₂)*$0.10 + n₂*$0.25 = $2.25
12*$0.10 - n₂*$0.10 + n₂*$0.25 = $2.25
$1.20 + n₂*$0.05*(5-2) = $2.25
$1.20 + n₂*$0.05*3 = $2.25
$1.20 + n₂*$0.15 = $2.25
n₂*$0.15 = $2.25 - $1.20
n₂*$0.15 = $1.05
n₂ = ($1.05)/($0.15)
n₂ = 7
If n₂ = 7:
n₁ + 7 = 12
Therefore, n₁ = 5.
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Answer:
5 dimes and 7 quarters.
