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Naddika [18.5K]
3 years ago
6

Josiah kept track of how many songs of each Germans were played in an hour from his MP3 player accounts are displayed in the tab

le below he has a total of 1500 songs on his players Josiah predicted the number of rock songs on the MP3 player to be 300 songs which statements about the solution is true select three choices
Mathematics
2 answers:
nata0808 [166]3 years ago
7 0

Answer:

a and b and e are the answers

Step-by-step explanation:

sergejj [24]3 years ago
3 0

Answer:

He should have found the average of the number of rock songs by averaging 4 and 6 to get 5.

He did not multiply the numerator and denominator by the correct number to equal 1,500.

He should have multiplied the numerator and denominator by 75, not 30

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Can someone help me please divide the following and then check by multiplying<br> 37,371\206
SCORPION-xisa [38]

Answer:

37,371 multiplied by 206 is 7,698,426

Step-by-step explanation:

Calculator.

6 0
3 years ago
Read 2 more answers
A. Find a value for x that makes -x less than 2x.
german

Answer:

it B find a value for x that make -x greater than 2x

6 0
2 years ago
Read 2 more answers
According to an​ article, 47​% of adults have experienced a breakup at least once during the last 10 years. Of 9 randomly select
In-s [12.5K]

Answer:

a) P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228

b) P(X=0)=(9C0)(0.47)^0 (1-0.47)^{9-0}=0.0033

And replacing we got:

P(X \geq 1)= 1-P(X

c) P(X=4)=(9C4)(0.47)^4 (1-0.47)^{9-4}=0.257

P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228

P(X=6)=(9C6)(0.47)^6 (1-0.47)^{9-6}=0.135

And adding we got:

P(4 \leq X \leq 6)= 0.257+0.228+0.135=0.620

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=9, p=0.47)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Assuming the following questions:

a. exactly five

For this case we can use the probability mass function and we got:

P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228

b. at least one

For this case we want this probability:

P(X \geq 1)

And we can use the complement rule and we got:

P(X \geq 1)= 1-P(X

P(X=0)=(9C0)(0.47)^0 (1-0.47)^{9-0}=0.0033

And replacing we got:

P(X \geq 1)= 1-P(X

c. between four and six, inclusive.

For this case we want this probability:

P(4 \leq X \leq 6)

P(X=4)=(9C4)(0.47)^4 (1-0.47)^{9-4}=0.257

P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228

P(X=6)=(9C6)(0.47)^6 (1-0.47)^{9-6}=0.135

And adding we got:

P(4 \leq X \leq 6)= 0.257+0.228+0.135=0.620

6 0
3 years ago
(06.02 MC)
mezya [45]

Step-by-step explanation:

<h3>Given</h3>
  • Side 1: 3x² - 2x - 1
  • Side 2: 9x + 2x² - 3
  • Perimeter:  5x³ + 4x² - x - 3
<h3>Part A</h3>

Sum of side lengths 1 and 2

  • 3x² - 2x - 1 + 9x + 2x² - 3 =
  • 5x² + 7x - 4
<h3>Part B</h3>

The perimeter is the sum of all three sides.

<u>The length of the third side is</u>

  • P - (side 1 + side 2) =
  • 5x³ + 4x² - x - 3 - (5x² + 7x - 4) =
  • 5x³ + 4x² - x - 3 - 5x² - 7x + 4 =
  • 5x³ - x² - 8x + 1

Part A - addition

Part B - subtraction

8 0
2 years ago
How do i Evaluate this expression?​
timofeeve [1]

\text{Hey there!}

\bf{9.83+8.2(7.01)}

\text{You could solved this equation by doing PEMDAS}

\text{PEMDAS simply means}\downarrow

\text{Parentheses }

\text{Exponents}

\text{Multiplication}

\text{Division}

\text{Addition}

\text{Subtraction}

\text{In your equation you have \bf{MULTIPLICATION \& ADDITION}}

\text{Now,  that we have every information we need.. lets solve the problem}

\text{We have to do \underline{MULITPLICATION} first then \underline{ADDITION} last}

\text{9.83 + 8.2(7.01)}

\text{8.2(7.01)=57.482}

\text{9.83 + 57.482 = 67.312}

\boxed{\boxed{\text{Thus your answer is most likely: \bf{67.312}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFIrst:)}

3 0
3 years ago
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