Quick answer I don't think this has an answer.
If you take the cos-1(2 sqrt(2)) your calculator should have a fit. Let's check that out. Mine certainly does. So there is something wrong with the question. If there is something to add in please do it and I will it least put an answer in the comments. As it stands, nothing will work.
If you put your calculator in radians, you will get an answer but it will not be anything resembling the choices you've listed.
If you meant sqrt(2) / 2 that would give 45o. Put it in your calculator like this 2 ^ 0.5 divided by 2 = 0.707
Cos - 1 (0.707) = 45
Answer:
5(3√x) +9(3√x) = 15√x+27√x= 42√x
5∛x + 9∛x = 14∛x
Step-by-step explanation:
Answer:
x = - 1
y = - 3
z = -2
Step-by-step explanation:
Please see steps in the image attached here.
So we want to know what percentage of bees would survive a virus after 19 days of decay if the bee population has a half life of 5 days. So every 5 days 50% of bees die. Lets say that N is the number of bees before the virus. So after 5 days is 50% less bees, so 50% of N remains. After another 5 days again, 50% bees die, and 50% out of 50% is 25%. So after 10 days, 25% of bees remain or 25%N or 0.25*N. After another 5 days its 12.5 % of bees remain or 0.125*N. And after 4 days 40% more bees die. And that is 0.4*0.125*N = 0.05N. 0.05*100% is 5%. So after 19 days, 5% of bees remain and 95% of bees is dead.
Answer:
3bat + 3b² - 6a²t²
Step-by-step explanation:
First you have to expand it to get;
3b(b - at) + 6at(b - at)
Then you can now multiply.
3b² - 3bat + 6bat - 6at²
Group like terms
6bat - 3bat + 3b² -6at²
3bat + 3b² - 6a²t²
