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r-ruslan [8.4K]
3 years ago
9

This table shows the input and output values for an exponential function f(x) .

Mathematics
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

Given the table as shown below:

x               y

-3             8/27

-2             8/9

-1             8/3

0              8

1              24

2              72

3              216

Taking any input variable x that are three apart:

i,e x = 0 and x = 3

The output values at x =0 and x = 3 are:

f(0) = 8 and f(3) = 216

Then;

The ratio of outputs is:

\frac{f(3)}{f(0)} = \frac{216}{8}= \frac{27}{1} or 27 : 1

Therefore, the ratio outputs for any two inputs that are three values apart is: 27: 1


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it is bigger then because 4/12 is in 72 Step-by-step explanation:

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How can I find the solution to a/5 + 8 is less than or equal to 13?
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Solve the problem. For a standard normal distribution, find the percentage of data that are between 3 standard deviations below
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Answer:

83.85%

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We will use the empirical rule. For a standard normal distribution the mean is equal to 0 and the standard deviation is equal to 1. Then, between 3 standard deviations below the mean, we have 2.35% + 13.5% + 34% = 49.85% of data, and 1 standard deviation above the mean we have 34% of data. Therefore, the percentage of data that are between 3 standard deviations below the mean and 1 standard deviation above the mean is 49.85%+34% = 83.85%.

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If f(x) = 2x2 + 1 and g(x) = x2 – 7, find (f – g)(x).
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6 0
4 years ago
The dimensions of a rectangle are √50a^3b^2 and √200a^3. What is the students error?
bearhunter [10]

Answer:

The student incorrectly simplified 30ab\sqrt{2a}+20a\sqrt{2a} .

Thus, option D is correct.

<u></u>

Step-by-step explanation:

The formula to determine the Perimeter of a rectangle of width w and length l is expressed as:

P = 2l + 2w

In other words, the perimeter can be determined by multiplying the length and width by 2 and adding the result.

In our case, the dimensions of a rectangle are \sqrt{50a^3b^2}  and  \sqrt{200a^3}\:\:.

Here is the student's solution:

2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}

                                 =10ab\sqrt{2a}+20a\sqrt{2a}

                                 =30ab\sqrt{2a}          

The student made an error in calculating 30ab\sqrt{2a}+20a\sqrt{2a} , because 30ab\sqrt{2a}+20a\sqrt{2a} are not like terms.

Hence, 30ab\sqrt{2a}+20a\sqrt{2a} can not be simplified to 30ab\sqrt{2a}

Therefore, the student incorrectly simplified 30ab\sqrt{2a}+20a\sqrt{2a} .

Thus, option D is correct.

<u></u>

<u></u>

<u>Here is the correct Solution:</u>

2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}

                                 =10ab\sqrt{2a}+20a\sqrt{2a}

7 0
3 years ago
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