A relation is a function if it has only One y-value for each x-value. Functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for f(x)=4x²+2x-6
<h3>What is a function?</h3>
A relation is a function if it has only One y-value for each x-value.
The given function is
f(x)=2x²-4x+2
Put x=2/3
f(2/3)=2(2/3)²-4(2/3)+2
=2(4/9)-8/3+2
=8/9-8/3+2
=(8-24+18)/9
f(2/3)=2/9
Now f(x)=4x²+2x-6
Put x=1/4
f(1/4)=4(1/4)²+2(1/4)-6
=4/16+2/4-6
=1/4+1/2-6
= 1+2-24/4
f(1/4)==-21/4
Hence functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for f(x)=4x²+2x-6
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Step-by-step explanation:
f(x) = x² + x + 3/4
in general, such a quadratic function is defined as
f(x) = a×x² + b×x + c
the solution for finding the values of x where a quadratic function value is 0 (there are as many solutions as the highest exponent of x, so 2 here in our case)
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = 1
c = 3/4
x = (-1 ± sqrt(1² - 4×1×3/4))/(2×1) =
= (-1 ± sqrt(1 - 3))/2 = (-1 ± sqrt(-2))/2 =
= (-1 ± sqrt(2)i)/2
x1 = (-1 + sqrt(2)i) / 2
x2 = (-1 - sqrt(2)i) / 2
remember, i = sqrt(-1)
f(x) has no 0 results for x = real numbers.
for the solution we need to use imaginary numbers.
I think the awswer should d
Answer:
y = 9x/5 + 50
Step-by-step explanation:
We are represent the information as coordinate (x,y)
If the cost for an order of 100 kilograms of steel bars is $230, this is expressed as (100, 230)
Also if the cost for an order of 150 kilograms of steel bars is $320, this is expressed as;
(150, 320)
Find the equation of a line passing through the points. The standard form of the equation is expressed as y = mx+c
m is the slope
c is the intercept
Get the slope;
m = y2-y1/x2-x1
m = 320-230/150-100
m = 90/50
m = 9/5
Get the y-intercept by substituting m = 9/5 and any point say (100, 230) into the expression y = mx+c
230 = 9/5(100)+c
230 = 9(20)+c
230 = 180 + c
c = 230-180
c = 50
Get the required equation
y = mx+c
y = 9/5 x + 50
Hence an equation for the cost of an order of steel bars (y) in terms of the weight of steel bars ordered (x) is y = 9x/5 + 50
Answer:
i thinkbit is C but im in 6th grade and at may 5 i. not there yet
