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AVprozaik [17]
2 years ago
6

Mira picked two numbers from a bowl. The difference of the two numbers was 4, and the sum of one-half of each number was 18. The

system that represents Mira’s numbers is below. 1/2x – 1/2y = 4 x + y = 18 Which two numbers did Mira pick?
a (10, 8)  b (18, 4)c (20, 16)d (40, 32)
Mathematics
2 answers:
crimeas [40]2 years ago
8 0

Answer:

Option C is correct

(20, 16)

Step-by-step explanation:

As per the statement:

Mira picked two numbers from a bowl. The difference of the two numbers was 4, and the sum of one-half of each number was 18

System of equation is given as:

\frac{1}{2}x+\frac{1}{2}y = 18            .....[1]

x-y = 4                                           .....[2]

Multiply both sides by 2 in [1] we have;

x+y = 36             ....[3]

Add equations [2] and [3] we have;

2x = 40

Divide both sides by 2 we have;

x = 20

Substitute the value of x in [2] we have;

20-y = 4

Subtract 20 from both sides we have;

-y = -16

Divide both sides by -1 we have;

y = 16

therefore, the two numbers did Mira pick is, (20, 16)

Makovka662 [10]2 years ago
5 0

since the difference between the numbers is 4

 do subtraction for the 4 possible answers, which one has a difference of 4?

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<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2  

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We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6  

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

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So, probability of getting more than 88.4 = 1 – area of z- score(2)

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Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

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Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0
3 years ago
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