Question

Mira picked two numbers from a bowl. The difference of the two numbers was 4, and the sum of one-half of each number was 18. The system that represents Mira’s numbers is below. 1/2x – 1/2y = 4 x + y = 18 Which two numbers did Mira pick?
a (10, 8)  b (18, 4)c (20, 16)d (40, 32)

Answer 1

Answer:

Option C is correct

(20, 16)

Step-by-step explanation:

As per the statement:

Mira picked two numbers from a bowl. The difference of the two numbers was 4, and the sum of one-half of each number was 18

System of equation is given as:

$\frac{1}{2}x+\frac{1}{2}y = 18$            .....[1]

$x-y = 4$                                           .....[2]

Multiply both sides by 2 in [1] we have;

$x+y = 36$             ....[3]

Add equations [2] and [3] we have;

2x = 40

Divide both sides by 2 we have;

x = 20

Substitute the value of x in [2] we have;

20-y = 4

Subtract 20 from both sides we have;

-y = -16

Divide both sides by -1 we have;

y = 16

therefore, the two numbers did Mira pick is, (20, 16)

Answer 2

since the difference between the numbers is 4

 do subtraction for the 4 possible answers, which one has a difference of 4?